Prime factorization of $$$2932$$$

Find the prime factorization of $$$2932$$$.

Start with the number $$$2$$$.

Determine whether $$$2932$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2932$$$ by $$${\color{green}2}$$$: $$$\frac{2932}{2} = {\color{red}1466}$$$.

Determine whether $$$1466$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1466$$$ by $$${\color{green}2}$$$: $$$\frac{1466}{2} = {\color{red}733}$$$.

The prime number $$${\color{green}733}$$$ has no other factors then $$$1$$$ and $$${\color{green}733}$$$: $$$\frac{733}{733} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2932 = 2^{2} \cdot 733$$$.

The prime factorization is $$$2932 = 2^{2} \cdot 733$$$A.