Prime factorization of $$$2908$$$

Find the prime factorization of $$$2908$$$.

Start with the number $$$2$$$.

Determine whether $$$2908$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2908$$$ by $$${\color{green}2}$$$: $$$\frac{2908}{2} = {\color{red}1454}$$$.

Determine whether $$$1454$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1454$$$ by $$${\color{green}2}$$$: $$$\frac{1454}{2} = {\color{red}727}$$$.

The prime number $$${\color{green}727}$$$ has no other factors then $$$1$$$ and $$${\color{green}727}$$$: $$$\frac{727}{727} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2908 = 2^{2} \cdot 727$$$.

The prime factorization is $$$2908 = 2^{2} \cdot 727$$$A.