Prime factorization of $$$2708$$$

Find the prime factorization of $$$2708$$$.

Start with the number $$$2$$$.

Determine whether $$$2708$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2708$$$ by $$${\color{green}2}$$$: $$$\frac{2708}{2} = {\color{red}1354}$$$.

Determine whether $$$1354$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1354$$$ by $$${\color{green}2}$$$: $$$\frac{1354}{2} = {\color{red}677}$$$.

The prime number $$${\color{green}677}$$$ has no other factors then $$$1$$$ and $$${\color{green}677}$$$: $$$\frac{677}{677} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2708 = 2^{2} \cdot 677$$$.

The prime factorization is $$$2708 = 2^{2} \cdot 677$$$A.