Prime factorization of $$$2620$$$

Find the prime factorization of $$$2620$$$.

Start with the number $$$2$$$.

Determine whether $$$2620$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2620$$$ by $$${\color{green}2}$$$: $$$\frac{2620}{2} = {\color{red}1310}$$$.

Determine whether $$$1310$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1310$$$ by $$${\color{green}2}$$$: $$$\frac{1310}{2} = {\color{red}655}$$$.

Determine whether $$$655$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$655$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$655$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$655$$$ by $$${\color{green}5}$$$: $$$\frac{655}{5} = {\color{red}131}$$$.

The prime number $$${\color{green}131}$$$ has no other factors then $$$1$$$ and $$${\color{green}131}$$$: $$$\frac{131}{131} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2620 = 2^{2} \cdot 5 \cdot 131$$$.

The prime factorization is $$$2620 = 2^{2} \cdot 5 \cdot 131$$$A.