Prime factorization of $$$2612$$$

Find the prime factorization of $$$2612$$$.

Start with the number $$$2$$$.

Determine whether $$$2612$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2612$$$ by $$${\color{green}2}$$$: $$$\frac{2612}{2} = {\color{red}1306}$$$.

Determine whether $$$1306$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1306$$$ by $$${\color{green}2}$$$: $$$\frac{1306}{2} = {\color{red}653}$$$.

The prime number $$${\color{green}653}$$$ has no other factors then $$$1$$$ and $$${\color{green}653}$$$: $$$\frac{653}{653} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2612 = 2^{2} \cdot 653$$$.

The prime factorization is $$$2612 = 2^{2} \cdot 653$$$A.