# Prime factorization of $2532$

The calculator will find the prime factorization of $2532$, with steps shown.

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Find the prime factorization of $2532$.

### Solution

Start with the number $2$.

Determine whether $2532$ is divisible by $2$.

It is divisible, thus, divide $2532$ by ${\color{green}2}$: $\frac{2532}{2} = {\color{red}1266}$.

Determine whether $1266$ is divisible by $2$.

It is divisible, thus, divide $1266$ by ${\color{green}2}$: $\frac{1266}{2} = {\color{red}633}$.

Determine whether $633$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $633$ is divisible by $3$.

It is divisible, thus, divide $633$ by ${\color{green}3}$: $\frac{633}{3} = {\color{red}211}$.

The prime number ${\color{green}211}$ has no other factors then $1$ and ${\color{green}211}$: $\frac{211}{211} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $2532 = 2^{2} \cdot 3 \cdot 211$.

The prime factorization is $2532 = 2^{2} \cdot 3 \cdot 211$A.