Prime factorization of $$$2484$$$

Find the prime factorization of $$$2484$$$.

Start with the number $$$2$$$.

Determine whether $$$2484$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2484$$$ by $$${\color{green}2}$$$: $$$\frac{2484}{2} = {\color{red}1242}$$$.

Determine whether $$$1242$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1242$$$ by $$${\color{green}2}$$$: $$$\frac{1242}{2} = {\color{red}621}$$$.

Determine whether $$$621$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$621$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$621$$$ by $$${\color{green}3}$$$: $$$\frac{621}{3} = {\color{red}207}$$$.

Determine whether $$$207$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$207$$$ by $$${\color{green}3}$$$: $$$\frac{207}{3} = {\color{red}69}$$$.

Determine whether $$$69$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$69$$$ by $$${\color{green}3}$$$: $$$\frac{69}{3} = {\color{red}23}$$$.

The prime number $$${\color{green}23}$$$ has no other factors then $$$1$$$ and $$${\color{green}23}$$$: $$$\frac{23}{23} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2484 = 2^{2} \cdot 3^{3} \cdot 23$$$.

The prime factorization is $$$2484 = 2^{2} \cdot 3^{3} \cdot 23$$$A.