Prime factorization of $$$2476$$$

Find the prime factorization of $$$2476$$$.

Start with the number $$$2$$$.

Determine whether $$$2476$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2476$$$ by $$${\color{green}2}$$$: $$$\frac{2476}{2} = {\color{red}1238}$$$.

Determine whether $$$1238$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1238$$$ by $$${\color{green}2}$$$: $$$\frac{1238}{2} = {\color{red}619}$$$.

The prime number $$${\color{green}619}$$$ has no other factors then $$$1$$$ and $$${\color{green}619}$$$: $$$\frac{619}{619} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2476 = 2^{2} \cdot 619$$$.

The prime factorization is $$$2476 = 2^{2} \cdot 619$$$A.