Prime factorization of $$$2404$$$

Find the prime factorization of $$$2404$$$.

Start with the number $$$2$$$.

Determine whether $$$2404$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2404$$$ by $$${\color{green}2}$$$: $$$\frac{2404}{2} = {\color{red}1202}$$$.

Determine whether $$$1202$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1202$$$ by $$${\color{green}2}$$$: $$$\frac{1202}{2} = {\color{red}601}$$$.

The prime number $$${\color{green}601}$$$ has no other factors then $$$1$$$ and $$${\color{green}601}$$$: $$$\frac{601}{601} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2404 = 2^{2} \cdot 601$$$.

The prime factorization is $$$2404 = 2^{2} \cdot 601$$$A.