Prime factorization of $$$2322$$$
Your Input
Find the prime factorization of $$$2322$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$2322$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2322$$$ by $$${\color{green}2}$$$: $$$\frac{2322}{2} = {\color{red}1161}$$$.
Determine whether $$$1161$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1161$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$1161$$$ by $$${\color{green}3}$$$: $$$\frac{1161}{3} = {\color{red}387}$$$.
Determine whether $$$387$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$387$$$ by $$${\color{green}3}$$$: $$$\frac{387}{3} = {\color{red}129}$$$.
Determine whether $$$129$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$129$$$ by $$${\color{green}3}$$$: $$$\frac{129}{3} = {\color{red}43}$$$.
The prime number $$${\color{green}43}$$$ has no other factors then $$$1$$$ and $$${\color{green}43}$$$: $$$\frac{43}{43} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2322 = 2 \cdot 3^{3} \cdot 43$$$.
Answer
The prime factorization is $$$2322 = 2 \cdot 3^{3} \cdot 43$$$A.