# Prime factorization of $2108$

The calculator will find the prime factorization of $2108$, with steps shown.

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Find the prime factorization of $2108$.

### Solution

Start with the number $2$.

Determine whether $2108$ is divisible by $2$.

It is divisible, thus, divide $2108$ by ${\color{green}2}$: $\frac{2108}{2} = {\color{red}1054}$.

Determine whether $1054$ is divisible by $2$.

It is divisible, thus, divide $1054$ by ${\color{green}2}$: $\frac{1054}{2} = {\color{red}527}$.

Determine whether $527$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $527$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $527$ is divisible by $5$.

Since it is not divisible, move to the next prime number.

The next prime number is $7$.

Determine whether $527$ is divisible by $7$.

Since it is not divisible, move to the next prime number.

The next prime number is $11$.

Determine whether $527$ is divisible by $11$.

Since it is not divisible, move to the next prime number.

The next prime number is $13$.

Determine whether $527$ is divisible by $13$.

Since it is not divisible, move to the next prime number.

The next prime number is $17$.

Determine whether $527$ is divisible by $17$.

It is divisible, thus, divide $527$ by ${\color{green}17}$: $\frac{527}{17} = {\color{red}31}$.

The prime number ${\color{green}31}$ has no other factors then $1$ and ${\color{green}31}$: $\frac{31}{31} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $2108 = 2^{2} \cdot 17 \cdot 31$.

The prime factorization is $2108 = 2^{2} \cdot 17 \cdot 31$A.