# Prime factorization of $1986$

The calculator will find the prime factorization of $1986$, with steps shown.

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Find the prime factorization of $1986$.

### Solution

Start with the number $2$.

Determine whether $1986$ is divisible by $2$.

It is divisible, thus, divide $1986$ by ${\color{green}2}$: $\frac{1986}{2} = {\color{red}993}$.

Determine whether $993$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $993$ is divisible by $3$.

It is divisible, thus, divide $993$ by ${\color{green}3}$: $\frac{993}{3} = {\color{red}331}$.

The prime number ${\color{green}331}$ has no other factors then $1$ and ${\color{green}331}$: $\frac{331}{331} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $1986 = 2 \cdot 3 \cdot 331$.

The prime factorization is $1986 = 2 \cdot 3 \cdot 331$A.