Prime factorization of $$$1986$$$
Your Input
Find the prime factorization of $$$1986$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$1986$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1986$$$ by $$${\color{green}2}$$$: $$$\frac{1986}{2} = {\color{red}993}$$$.
Determine whether $$$993$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$993$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$993$$$ by $$${\color{green}3}$$$: $$$\frac{993}{3} = {\color{red}331}$$$.
The prime number $$${\color{green}331}$$$ has no other factors then $$$1$$$ and $$${\color{green}331}$$$: $$$\frac{331}{331} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1986 = 2 \cdot 3 \cdot 331$$$.
Answer
The prime factorization is $$$1986 = 2 \cdot 3 \cdot 331$$$A.