# Prime factorization of $1758$

The calculator will find the prime factorization of $1758$, with steps shown.

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Find the prime factorization of $1758$.

### Solution

Start with the number $2$.

Determine whether $1758$ is divisible by $2$.

It is divisible, thus, divide $1758$ by ${\color{green}2}$: $\frac{1758}{2} = {\color{red}879}$.

Determine whether $879$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $879$ is divisible by $3$.

It is divisible, thus, divide $879$ by ${\color{green}3}$: $\frac{879}{3} = {\color{red}293}$.

The prime number ${\color{green}293}$ has no other factors then $1$ and ${\color{green}293}$: $\frac{293}{293} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $1758 = 2 \cdot 3 \cdot 293$.

The prime factorization is $1758 = 2 \cdot 3 \cdot 293$A.