Prime factorization of $$$1732$$$
Your Input
Find the prime factorization of $$$1732$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$1732$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1732$$$ by $$${\color{green}2}$$$: $$$\frac{1732}{2} = {\color{red}866}$$$.
Determine whether $$$866$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$866$$$ by $$${\color{green}2}$$$: $$$\frac{866}{2} = {\color{red}433}$$$.
The prime number $$${\color{green}433}$$$ has no other factors then $$$1$$$ and $$${\color{green}433}$$$: $$$\frac{433}{433} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1732 = 2^{2} \cdot 433$$$.
Answer
The prime factorization is $$$1732 = 2^{2} \cdot 433$$$A.