Prime factorization of $$$1492$$$

Find the prime factorization of $$$1492$$$.

Start with the number $$$2$$$.

Determine whether $$$1492$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1492$$$ by $$${\color{green}2}$$$: $$$\frac{1492}{2} = {\color{red}746}$$$.

Determine whether $$$746$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$746$$$ by $$${\color{green}2}$$$: $$$\frac{746}{2} = {\color{red}373}$$$.

The prime number $$${\color{green}373}$$$ has no other factors then $$$1$$$ and $$${\color{green}373}$$$: $$$\frac{373}{373} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1492 = 2^{2} \cdot 373$$$.

The prime factorization is $$$1492 = 2^{2} \cdot 373$$$A.