# Prime factorization of $1492$

The calculator will find the prime factorization of $1492$, with steps shown.

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Find the prime factorization of $1492$.

### Solution

Start with the number $2$.

Determine whether $1492$ is divisible by $2$.

It is divisible, thus, divide $1492$ by ${\color{green}2}$: $\frac{1492}{2} = {\color{red}746}$.

Determine whether $746$ is divisible by $2$.

It is divisible, thus, divide $746$ by ${\color{green}2}$: $\frac{746}{2} = {\color{red}373}$.

The prime number ${\color{green}373}$ has no other factors then $1$ and ${\color{green}373}$: $\frac{373}{373} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $1492 = 2^{2} \cdot 373$.

The prime factorization is $1492 = 2^{2} \cdot 373$A.