Prime factorization of $$$1415$$$

Find the prime factorization of $$$1415$$$.

Start with the number $$$2$$$.

Determine whether $$$1415$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$1415$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$1415$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$1415$$$ by $$${\color{green}5}$$$: $$$\frac{1415}{5} = {\color{red}283}$$$.

The prime number $$${\color{green}283}$$$ has no other factors then $$$1$$$ and $$${\color{green}283}$$$: $$$\frac{283}{283} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1415 = 5 \cdot 283$$$.

The prime factorization is $$$1415 = 5 \cdot 283$$$A.