# Prime factorization of $1398$

The calculator will find the prime factorization of $1398$, with steps shown.

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Find the prime factorization of $1398$.

### Solution

Start with the number $2$.

Determine whether $1398$ is divisible by $2$.

It is divisible, thus, divide $1398$ by ${\color{green}2}$: $\frac{1398}{2} = {\color{red}699}$.

Determine whether $699$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $699$ is divisible by $3$.

It is divisible, thus, divide $699$ by ${\color{green}3}$: $\frac{699}{3} = {\color{red}233}$.

The prime number ${\color{green}233}$ has no other factors then $1$ and ${\color{green}233}$: $\frac{233}{233} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $1398 = 2 \cdot 3 \cdot 233$.

The prime factorization is $1398 = 2 \cdot 3 \cdot 233$A.