Prime factorization of $$$1299$$$

Find the prime factorization of $$$1299$$$.

Start with the number $$$2$$$.

Determine whether $$$1299$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$1299$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1299$$$ by $$${\color{green}3}$$$: $$$\frac{1299}{3} = {\color{red}433}$$$.

The prime number $$${\color{green}433}$$$ has no other factors then $$$1$$$ and $$${\color{green}433}$$$: $$$\frac{433}{433} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1299 = 3 \cdot 433$$$.

The prime factorization is $$$1299 = 3 \cdot 433$$$A.