Ολοκλήρωμα του $$$2 \ln\left(\sin{\left(x \right)}\right) \sin^{6}{\left(x \right)} \cos{\left(x \right)}$$$

Βρείτε $$$\int 2 \ln\left(\sin{\left(x \right)}\right) \sin^{6}{\left(x \right)} \cos{\left(x \right)}\, dx$$$.

Εφαρμόστε τον κανόνα του σταθερού πολλαπλασίου $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ με $$$c=2$$$ και $$$f{\left(x \right)} = \ln{\left(\sin{\left(x \right)} \right)} \sin^{6}{\left(x \right)} \cos{\left(x \right)}$$$:

$${\color{red}{\int{2 \ln{\left(\sin{\left(x \right)} \right)} \sin^{6}{\left(x \right)} \cos{\left(x \right)} d x}}} = {\color{red}{\left(2 \int{\ln{\left(\sin{\left(x \right)} \right)} \sin^{6}{\left(x \right)} \cos{\left(x \right)} d x}\right)}}$$

Έστω $$$u=\sin{\left(x \right)}$$$.

Τότε $$$du=\left(\sin{\left(x \right)}\right)^{\prime }dx = \cos{\left(x \right)} dx$$$ (τα βήματα παρουσιάζονται »), και έχουμε ότι $$$\cos{\left(x \right)} dx = du$$$.

Επομένως,

$$2 {\color{red}{\int{\ln{\left(\sin{\left(x \right)} \right)} \sin^{6}{\left(x \right)} \cos{\left(x \right)} d x}}} = 2 {\color{red}{\int{u^{6} \ln{\left(u \right)} d u}}}$$

Για το ολοκλήρωμα $$$\int{u^{6} \ln{\left(u \right)} d u}$$$, χρησιμοποιήστε την ολοκλήρωση κατά μέρη $$$\int \operatorname{\kappa} \operatorname{dv} = \operatorname{\kappa}\operatorname{v} - \int \operatorname{v} \operatorname{d\kappa}$$$.

Έστω $$$\operatorname{\kappa}=\ln{\left(u \right)}$$$ και $$$\operatorname{dv}=u^{6} du$$$.

Τότε $$$\operatorname{d\kappa}=\left(\ln{\left(u \right)}\right)^{\prime }du=\frac{du}{u}$$$ (τα βήματα φαίνονται ») και $$$\operatorname{v}=\int{u^{6} d u}=\frac{u^{7}}{7}$$$ (τα βήματα φαίνονται »).

Επομένως,

$$2 {\color{red}{\int{u^{6} \ln{\left(u \right)} d u}}}=2 {\color{red}{\left(\ln{\left(u \right)} \cdot \frac{u^{7}}{7}-\int{\frac{u^{7}}{7} \cdot \frac{1}{u} d u}\right)}}=2 {\color{red}{\left(\frac{u^{7} \ln{\left(u \right)}}{7} - \int{\frac{u^{6}}{7} d u}\right)}}$$

Εφαρμόστε τον κανόνα του σταθερού πολλαπλασίου $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ με $$$c=\frac{1}{7}$$$ και $$$f{\left(u \right)} = u^{6}$$$:

$$\frac{2 u^{7} \ln{\left(u \right)}}{7} - 2 {\color{red}{\int{\frac{u^{6}}{7} d u}}} = \frac{2 u^{7} \ln{\left(u \right)}}{7} - 2 {\color{red}{\left(\frac{\int{u^{6} d u}}{7}\right)}}$$

Εφαρμόστε τον κανόνα δύναμης $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ με $$$n=6$$$:

$$\frac{2 u^{7} \ln{\left(u \right)}}{7} - \frac{2 {\color{red}{\int{u^{6} d u}}}}{7}=\frac{2 u^{7} \ln{\left(u \right)}}{7} - \frac{2 {\color{red}{\frac{u^{1 + 6}}{1 + 6}}}}{7}=\frac{2 u^{7} \ln{\left(u \right)}}{7} - \frac{2 {\color{red}{\left(\frac{u^{7}}{7}\right)}}}{7}$$

Θυμηθείτε ότι $$$u=\sin{\left(x \right)}$$$:

$$- \frac{2 {\color{red}{u}}^{7}}{49} + \frac{2 {\color{red}{u}}^{7} \ln{\left({\color{red}{u}} \right)}}{7} = - \frac{2 {\color{red}{\sin{\left(x \right)}}}^{7}}{49} + \frac{2 {\color{red}{\sin{\left(x \right)}}}^{7} \ln{\left({\color{red}{\sin{\left(x \right)}}} \right)}}{7}$$

Επομένως,

$$\int{2 \ln{\left(\sin{\left(x \right)} \right)} \sin^{6}{\left(x \right)} \cos{\left(x \right)} d x} = \frac{2 \ln{\left(\sin{\left(x \right)} \right)} \sin^{7}{\left(x \right)}}{7} - \frac{2 \sin^{7}{\left(x \right)}}{49}$$

Απλοποιήστε:

$$\int{2 \ln{\left(\sin{\left(x \right)} \right)} \sin^{6}{\left(x \right)} \cos{\left(x \right)} d x} = \frac{2 \left(7 \ln{\left(\sin{\left(x \right)} \right)} - 1\right) \sin^{7}{\left(x \right)}}{49}$$

Προσθέστε τη σταθερά ολοκλήρωσης:

$$\int{2 \ln{\left(\sin{\left(x \right)} \right)} \sin^{6}{\left(x \right)} \cos{\left(x \right)} d x} = \frac{2 \left(7 \ln{\left(\sin{\left(x \right)} \right)} - 1\right) \sin^{7}{\left(x \right)}}{49}+C$$

$$$\int 2 \ln\left(\sin{\left(x \right)}\right) \sin^{6}{\left(x \right)} \cos{\left(x \right)}\, dx = \frac{2 \left(7 \ln\left(\sin{\left(x \right)}\right) - 1\right) \sin^{7}{\left(x \right)}}{49} + C$$$A