Integral of $$$\frac{1}{x^{7}}$$$

Find $$$\int \frac{1}{x^{7}}\, dx$$$.

Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=-7$$$:

$${\color{red}{\int{\frac{1}{x^{7}} d x}}}={\color{red}{\int{x^{-7} d x}}}={\color{red}{\frac{x^{-7 + 1}}{-7 + 1}}}={\color{red}{\left(- \frac{x^{-6}}{6}\right)}}={\color{red}{\left(- \frac{1}{6 x^{6}}\right)}}$$

Therefore,

$$\int{\frac{1}{x^{7}} d x} = - \frac{1}{6 x^{6}}$$

Add the constant of integration:

$$\int{\frac{1}{x^{7}} d x} = - \frac{1}{6 x^{6}}+C$$

$$$\int \frac{1}{x^{7}}\, dx = - \frac{1}{6 x^{6}} + C$$$A