Definite and Improper Integral Calculator

The calculator will try to evaluate the definite (i.e. with bounds) integral, including improper, with steps shown.

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If you need `-oo`, type -inf.

Enter an upper limit:

If you need `oo`, type inf.

Please write without any differentials such as `dx`, `dy` etc.

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Solution

Your input: calculate $$$\int_{6}^{\infty}\left( \frac{e^{- \frac{1}{x}}}{x^{2}} \right)dx$$$

First, calculate the corresponding indefinite integral: $$$\int{\frac{e^{- \frac{1}{x}}}{x^{2}} d x}=e^{- \frac{1}{x}}$$$ (for steps, see indefinite integral calculator)

Since there is infinity in the upper bound, this is improper integral of type 1.

To evaluate an integral over an interval, we use the Fundamental Theorem of Calculus. However, we need to use limit if an endpoint of the interval is special (infinite).

$$$\int_{6}^{\infty}\left( \frac{e^{- \frac{1}{x}}}{x^{2}} \right)dx=\lim_{x \to \infty}\left(e^{- \frac{1}{x}}\right)-\left(e^{- \frac{1}{x}}\right)|_{\left(x=6\right)}=1 - e^{- \frac{1}{6}}$$$

Answer: $$$\int_{6}^{\infty}\left( \frac{e^{- \frac{1}{x}}}{x^{2}} \right)dx=1 - e^{- \frac{1}{6}}\approx 0.153518275109386$$$

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Definite and Improper Integral Calculator

Calculate definite and improper integrals step by step

Solution