矩陣乘法計算器
逐步計算矩陣乘積
您的輸入
計算 $$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right]$$$。
解答
$$$\left[\begin{array}{ccc}{\color{DarkBlue}4} & {\color{Crimson}5} & {\color{Magenta}7}\\{\color{Peru}2} & {\color{Blue}1} & {\color{OrangeRed}0}\end{array}\right]\cdot \left[\begin{array}{cc}{\color{Red}2} & {\color{Violet}3}\\{\color{Chartreuse}8} & {\color{GoldenRod}9}\\{\color{DarkMagenta}1} & {\color{Fuchsia}1}\end{array}\right] = \left[\begin{array}{cc}{\color{DarkBlue}\left(4\right)}\cdot {\color{Red}\left(2\right)} + {\color{Crimson}\left(5\right)}\cdot {\color{Chartreuse}\left(8\right)} + {\color{Magenta}\left(7\right)}\cdot {\color{DarkMagenta}\left(1\right)} & {\color{DarkBlue}\left(4\right)}\cdot {\color{Violet}\left(3\right)} + {\color{Crimson}\left(5\right)}\cdot {\color{GoldenRod}\left(9\right)} + {\color{Magenta}\left(7\right)}\cdot {\color{Fuchsia}\left(1\right)}\\{\color{Peru}\left(2\right)}\cdot {\color{Red}\left(2\right)} + {\color{Blue}\left(1\right)}\cdot {\color{Chartreuse}\left(8\right)} + {\color{OrangeRed}\left(0\right)}\cdot {\color{DarkMagenta}\left(1\right)} & {\color{Peru}\left(2\right)}\cdot {\color{Violet}\left(3\right)} + {\color{Blue}\left(1\right)}\cdot {\color{GoldenRod}\left(9\right)} + {\color{OrangeRed}\left(0\right)}\cdot {\color{Fuchsia}\left(1\right)}\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$
答案
$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$A