矩陣乘法計算器
逐步計算矩陣乘積
您的輸入
計算 $$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right]$$$。
解答
$$$\left[\begin{array}{ccc}{\color{Purple}4} & {\color{Green}5} & {\color{DeepPink}7}\\{\color{BlueViolet}2} & {\color{DarkCyan}1} & {\color{OrangeRed}0}\end{array}\right]\cdot \left[\begin{array}{cc}{\color{Red}2} & {\color{GoldenRod}3}\\{\color{Green}8} & {\color{DarkBlue}9}\\{\color{OrangeRed}1} & {\color{DeepPink}1}\end{array}\right] = \left[\begin{array}{cc}{\color{Purple}\left(4\right)}\cdot {\color{Red}\left(2\right)} + {\color{Green}\left(5\right)}\cdot {\color{Green}\left(8\right)} + {\color{DeepPink}\left(7\right)}\cdot {\color{OrangeRed}\left(1\right)} & {\color{Purple}\left(4\right)}\cdot {\color{GoldenRod}\left(3\right)} + {\color{Green}\left(5\right)}\cdot {\color{DarkBlue}\left(9\right)} + {\color{DeepPink}\left(7\right)}\cdot {\color{DeepPink}\left(1\right)}\\{\color{BlueViolet}\left(2\right)}\cdot {\color{Red}\left(2\right)} + {\color{DarkCyan}\left(1\right)}\cdot {\color{Green}\left(8\right)} + {\color{OrangeRed}\left(0\right)}\cdot {\color{OrangeRed}\left(1\right)} & {\color{BlueViolet}\left(2\right)}\cdot {\color{GoldenRod}\left(3\right)} + {\color{DarkCyan}\left(1\right)}\cdot {\color{DarkBlue}\left(9\right)} + {\color{OrangeRed}\left(0\right)}\cdot {\color{DeepPink}\left(1\right)}\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$
答案
$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$A