複數根計算器
逐步求解複數的根與單位根
此計算器將使用棣莫弗公式求出給定複數的第$$$n$$$次方根，並顯示步驟。
您的輸入
求$$$\sqrt[4]{81 i}$$$。
解答
$$$81 i$$$ 的極座標形式為 $$$81 \left(\cos{\left(\frac{\pi}{2} \right)} + i \sin{\left(\frac{\pi}{2} \right)}\right)$$$（步驟請參見 極座標形式計算器）。
根據棣莫弗公式，複數 $$$r \left(\cos{\left(\theta \right)} + i \sin{\left(\theta \right)}\right)$$$ 的所有第 $$$n$$$ 次方根由 $$$r^{\frac{1}{n}} \left(\cos{\left(\frac{\theta + 2 \pi k}{n} \right)} + i \sin{\left(\frac{\theta + 2 \pi k}{n} \right)}\right)$$$, $$$k=\overline{0..n-1}$$$ 給出。
我們有 $$$r = 81$$$、$$$\theta = \frac{\pi}{2}$$$ 和 $$$n = 4$$$。
- $$$k = 0$$$: $$$\sqrt[4]{81} \left(\cos{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 0}{4} \right)} + i \sin{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 0}{4} \right)}\right) = 3 \left(\cos{\left(\frac{\pi}{8} \right)} + i \sin{\left(\frac{\pi}{8} \right)}\right) = 3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}} + 3 i \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}$$$
- $$$k = 1$$$: $$$\sqrt[4]{81} \left(\cos{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 1}{4} \right)} + i \sin{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 1}{4} \right)}\right) = 3 \left(\cos{\left(\frac{5 \pi}{8} \right)} + i \sin{\left(\frac{5 \pi}{8} \right)}\right) = - 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} + 3 i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}$$$
- $$$k = 2$$$: $$$\sqrt[4]{81} \left(\cos{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 2}{4} \right)} + i \sin{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 2}{4} \right)}\right) = 3 \left(\cos{\left(\frac{9 \pi}{8} \right)} + i \sin{\left(\frac{9 \pi}{8} \right)}\right) = - 3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}} - 3 i \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}$$$
- $$$k = 3$$$: $$$\sqrt[4]{81} \left(\cos{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 3}{4} \right)} + i \sin{\left(\frac{\frac{\pi}{2} + 2\cdot \pi\cdot 3}{4} \right)}\right) = 3 \left(\cos{\left(\frac{13 \pi}{8} \right)} + i \sin{\left(\frac{13 \pi}{8} \right)}\right) = 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} - 3 i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}$$$
答案
$$$\sqrt[4]{81 i} = 3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}} + 3 i \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}\approx 2.77163859753386 + 1.148050297095269 i$$$A
$$$\sqrt[4]{81 i} = - 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} + 3 i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}\approx -1.148050297095269 + 2.77163859753386 i$$$A
$$$\sqrt[4]{81 i} = - 3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}} - 3 i \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}\approx -2.77163859753386 - 1.148050297095269 i$$$A
$$$\sqrt[4]{81 i} = 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} - 3 i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}\approx 1.148050297095269 - 2.77163859753386 i$$$A