矩阵乘法计算器

计算 $$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right]$$$。

$$$\left[\begin{array}{ccc}{\color{BlueViolet}4} & {\color{Red}5} & {\color{DarkMagenta}7}\\{\color{Crimson}2} & {\color{Violet}1} & {\color{Green}0}\end{array}\right]\cdot \left[\begin{array}{cc}{\color{Green}2} & {\color{GoldenRod}3}\\{\color{Red}8} & {\color{Crimson}9}\\{\color{Purple}1} & {\color{DarkMagenta}1}\end{array}\right] = \left[\begin{array}{cc}{\color{BlueViolet}\left(4\right)}\cdot {\color{Green}\left(2\right)} + {\color{Red}\left(5\right)}\cdot {\color{Red}\left(8\right)} + {\color{DarkMagenta}\left(7\right)}\cdot {\color{Purple}\left(1\right)} & {\color{BlueViolet}\left(4\right)}\cdot {\color{GoldenRod}\left(3\right)} + {\color{Red}\left(5\right)}\cdot {\color{Crimson}\left(9\right)} + {\color{DarkMagenta}\left(7\right)}\cdot {\color{DarkMagenta}\left(1\right)}\\{\color{Crimson}\left(2\right)}\cdot {\color{Green}\left(2\right)} + {\color{Violet}\left(1\right)}\cdot {\color{Red}\left(8\right)} + {\color{Green}\left(0\right)}\cdot {\color{Purple}\left(1\right)} & {\color{Crimson}\left(2\right)}\cdot {\color{GoldenRod}\left(3\right)} + {\color{Violet}\left(1\right)}\cdot {\color{Crimson}\left(9\right)} + {\color{Green}\left(0\right)}\cdot {\color{DarkMagenta}\left(1\right)}\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$

$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$A