矩阵乘法计算器
逐步计算矩阵乘法
您的输入
计算 $$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right]$$$。
解答
$$$\left[\begin{array}{ccc}{\color{Violet}4} & {\color{Blue}5} & {\color{GoldenRod}7}\\{\color{Chocolate}2} & {\color{DeepPink}1} & {\color{OrangeRed}0}\end{array}\right]\cdot \left[\begin{array}{cc}{\color{Fuchsia}2} & {\color{Red}3}\\{\color{Purple}8} & {\color{DarkCyan}9}\\{\color{Brown}1} & {\color{Blue}1}\end{array}\right] = \left[\begin{array}{cc}{\color{Violet}\left(4\right)}\cdot {\color{Fuchsia}\left(2\right)} + {\color{Blue}\left(5\right)}\cdot {\color{Purple}\left(8\right)} + {\color{GoldenRod}\left(7\right)}\cdot {\color{Brown}\left(1\right)} & {\color{Violet}\left(4\right)}\cdot {\color{Red}\left(3\right)} + {\color{Blue}\left(5\right)}\cdot {\color{DarkCyan}\left(9\right)} + {\color{GoldenRod}\left(7\right)}\cdot {\color{Blue}\left(1\right)}\\{\color{Chocolate}\left(2\right)}\cdot {\color{Fuchsia}\left(2\right)} + {\color{DeepPink}\left(1\right)}\cdot {\color{Purple}\left(8\right)} + {\color{OrangeRed}\left(0\right)}\cdot {\color{Brown}\left(1\right)} & {\color{Chocolate}\left(2\right)}\cdot {\color{Red}\left(3\right)} + {\color{DeepPink}\left(1\right)}\cdot {\color{DarkCyan}\left(9\right)} + {\color{OrangeRed}\left(0\right)}\cdot {\color{Blue}\left(1\right)}\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$
答案
$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\end{array}\right]\cdot \left[\begin{array}{cc}2 & 3\\8 & 9\\1 & 1\end{array}\right] = \left[\begin{array}{cc}55 & 64\\12 & 15\end{array}\right]$$$A