|
|
|
|
|
|
|
|
|
|
|
|
化简 $$$\left(A \cdot B\right) + \left(B \cdot C\right) + \left(A \cdot \overline{C}\right)$$$
相关计算器: 真值表计算器
您的输入
化简布尔表达式 $$$\left(A \cdot B\right) + \left(B \cdot C\right) + \left(A \cdot \overline{C}\right)$$$。
解答
应用共识定律 $$$\left(x \cdot y\right) + \left(\overline{x} \cdot z\right) + \left(y \cdot z\right) = \left(x \cdot y\right) + \left(\overline{x} \cdot z\right)$$$，取 $$$x = C$$$、$$$y = B$$$ 和 $$$z = A$$$ 为：
$${\color{red}\left(\left(A \cdot B\right) + \left(B \cdot C\right) + \left(A \cdot \overline{C}\right)\right)} = {\color{red}\left(\left(C \cdot B\right) + \left(\overline{C} \cdot A\right)\right)}$$答案
$$$\left(A \cdot B\right) + \left(B \cdot C\right) + \left(A \cdot \overline{C}\right) = \left(C \cdot B\right) + \left(\overline{C} \cdot A\right)$$$
Please try a new game Rotatly