雅可比矩阵计算器

逐步计算雅可比矩阵

该计算器将求出函数组的雅可比矩阵以及(若可能)雅可比行列式,并显示步骤。

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您的输入

计算$$$\left\{x = r \cos{\left(\theta \right)}, y = r \sin{\left(\theta \right)}\right\}$$$的雅可比矩阵。

解答

雅可比矩阵定义如下:$$$J{\left(x,y \right)}\left(r, \theta\right) = \left[\begin{array}{cc}\frac{\partial x}{\partial r} & \frac{\partial x}{\partial \theta}\\\frac{\partial y}{\partial r} & \frac{\partial y}{\partial \theta}\end{array}\right]$$$

在我们的情况下,$$$J{\left(x,y \right)}\left(r, \theta\right) = \left[\begin{array}{cc}\frac{\partial}{\partial r} \left(r \cos{\left(\theta \right)}\right) & \frac{\partial}{\partial \theta} \left(r \cos{\left(\theta \right)}\right)\\\frac{\partial}{\partial r} \left(r \sin{\left(\theta \right)}\right) & \frac{\partial}{\partial \theta} \left(r \sin{\left(\theta \right)}\right)\end{array}\right]$$$

求导数(步骤详见导数计算器):$$$J{\left(x,y \right)}\left(r, \theta\right) = \left[\begin{array}{cc}\cos{\left(\theta \right)} & - r \sin{\left(\theta \right)}\\\sin{\left(\theta \right)} & r \cos{\left(\theta \right)}\end{array}\right]$$$

雅可比行列式是雅可比矩阵的行列式:$$$\left|\begin{array}{cc}\cos{\left(\theta \right)} & - r \sin{\left(\theta \right)}\\\sin{\left(\theta \right)} & r \cos{\left(\theta \right)}\end{array}\right| = r$$$(步骤见行列式计算器)。

答案

雅可比矩阵为 $$$\left[\begin{array}{cc}\cos{\left(\theta \right)} & - r \sin{\left(\theta \right)}\\\sin{\left(\theta \right)} & r \cos{\left(\theta \right)}\end{array}\right]$$$A

雅可比行列式为 $$$r$$$A


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