解方程 $$$\left(x + 9\right)^{2} + 36 = 102$$$,求$$$x$$$(实根)
您的输入
在区间$$$\left(-\infty, \infty\right)$$$上求解关于$$$x$$$的方程$$$\left(x + 9\right)^{2} + 36 = 102$$$。
答案
实根
$$$x = -9 + \sqrt{66}\approx -0.87596159536404$$$A
$$$x = -9 - \sqrt{66}\approx -17.12403840463596$$$A
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