复合函数计算器

逐步求解函数的复合

该计算器将求出函数 $$$f(x)$$$$$$g(x)$$$ 的复合 $$$(f\circ g)(x)$$$$$$(g\circ f)(x)$$$$$$(f\circ f)(x)$$$$$$(f\circ g)(x)$$$,并显示步骤。如有需要,还会在指定点对这些复合进行求值。

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您的输入

$$$f{\left(x \right)} = \frac{1}{x^{2} + x}$$$$$$g{\left(x \right)} = x + 7$$$的复合函数。

解答

$$$\left(f\circ g\right)\left(x\right) = f\left(g\left(x\right)\right) = f\left(x + 7\right) = \frac{1}{{\color{red}\left(x + 7\right)}^{2} + {\color{red}\left(x + 7\right)}} = \frac{1}{\left(x + 7\right) \left(x + 8\right)}$$$

$$$\left(g\circ f\right)\left(x\right) = g\left(f\left(x\right)\right) = g\left(\frac{1}{x^{2} + x}\right) = {\color{red}\left(\frac{1}{x^{2} + x}\right)} + 7 = 7 + \frac{1}{x^{2} + x}$$$

$$$\left(f\circ f\right)\left(x\right) = f\left(f\left(x\right)\right) = f\left(\frac{1}{x^{2} + x}\right) = \frac{1}{{\color{red}\left(\frac{1}{x^{2} + x}\right)}^{2} + {\color{red}\left(\frac{1}{x^{2} + x}\right)}} = \frac{x^{2} \left(x + 1\right)^{2}}{x^{2} + x + 1}$$$

$$$\left(g\circ g\right)\left(x\right) = g\left(g\left(x\right)\right) = g\left(x + 7\right) = {\color{red}\left(x + 7\right)} + 7 = x + 14$$$

答案

$$$\left(f\circ g\right)\left(x\right) = \frac{1}{\left(x + 7\right) \left(x + 8\right)}$$$A

$$$\left(g\circ f\right)\left(x\right) = 7 + \frac{1}{x^{2} + x}$$$A

$$$\left(f\circ f\right)\left(x\right) = \frac{x^{2} \left(x + 1\right)^{2}}{x^{2} + x + 1}$$$A

$$$\left(g\circ g\right)\left(x\right) = x + 14$$$A