$$$\frac{\sqrt{2}}{2} \left[\begin{array}{ccc}0 & \sqrt{2} & 0\\1 & 2 & 1\\1 & 0 & 1\end{array}\right]$$$

Hesaplayıcı, $$$3$$$x$$$3$$$ boyutlu $$$\left[\begin{array}{ccc}0 & \sqrt{2} & 0\\1 & 2 & 1\\1 & 0 & 1\end{array}\right]$$$ matrisini skaler $$$\frac{\sqrt{2}}{2}$$$ ile adımları gösterilerek çarpacaktır.
$$$\times$$$
A

Hesap makinesi bir şeyi hesaplayamadıysa, bir hata tespit ettiyseniz veya bir öneriniz/geri bildiriminiz varsa, lütfen bizimle iletişime geçin.

Girdiniz

Hesaplayın $$$\frac{\sqrt{2}}{2} \left[\begin{array}{ccc}0 & \sqrt{2} & 0\\1 & 2 & 1\\1 & 0 & 1\end{array}\right]$$$.

Çözüm

Matristeki her bir elemanı skalerle çarpın:

$$${\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left[\begin{array}{ccc}0 & \sqrt{2} & 0\\1 & 2 & 1\\1 & 0 & 1\end{array}\right] = \left[\begin{array}{ccc}{\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(0\right) & {\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(\sqrt{2}\right) & {\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(0\right)\\{\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(1\right) & {\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(2\right) & {\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(1\right)\\{\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(1\right) & {\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(0\right) & {\color{DeepPink}\left(\frac{\sqrt{2}}{2}\right)}\cdot \left(1\right)\end{array}\right] = \left[\begin{array}{ccc}0 & 1 & 0\\\frac{\sqrt{2}}{2} & \sqrt{2} & \frac{\sqrt{2}}{2}\\\frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2}\end{array}\right]$$$

Cevap

$$$\frac{\sqrt{2}}{2} \left[\begin{array}{ccc}0 & \sqrt{2} & 0\\1 & 2 & 1\\1 & 0 & 1\end{array}\right] = \left[\begin{array}{ccc}0 & 1 & 0\\\frac{\sqrt{2}}{2} & \sqrt{2} & \frac{\sqrt{2}}{2}\\\frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2}\end{array}\right]\approx \left[\begin{array}{ccc}0 & 1 & 0\\0.707106781186548 & 1.414213562373095 & 0.707106781186548\\0.707106781186548 & 0 & 0.707106781186548\end{array}\right]$$$A


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