$$$x^{4} - \frac{1}{4 x^{4}}$$$'nin integrali

Bulun: $$$\int \left(x^{4} - \frac{1}{4 x^{4}}\right)\, dx$$$.

Her terimin integralini alın:

$${\color{red}{\int{\left(x^{4} - \frac{1}{4 x^{4}}\right)d x}}} = {\color{red}{\left(- \int{\frac{1}{4 x^{4}} d x} + \int{x^{4} d x}\right)}}$$

Kuvvet kuralını $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ $$$n=4$$$ ile uygulayın:

$$- \int{\frac{1}{4 x^{4}} d x} + {\color{red}{\int{x^{4} d x}}}=- \int{\frac{1}{4 x^{4}} d x} + {\color{red}{\frac{x^{1 + 4}}{1 + 4}}}=- \int{\frac{1}{4 x^{4}} d x} + {\color{red}{\left(\frac{x^{5}}{5}\right)}}$$

Sabit katsayı kuralı $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$'i $$$c=\frac{1}{4}$$$ ve $$$f{\left(x \right)} = \frac{1}{x^{4}}$$$ ile uygula:

$$\frac{x^{5}}{5} - {\color{red}{\int{\frac{1}{4 x^{4}} d x}}} = \frac{x^{5}}{5} - {\color{red}{\left(\frac{\int{\frac{1}{x^{4}} d x}}{4}\right)}}$$

Kuvvet kuralını $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ $$$n=-4$$$ ile uygulayın:

$$\frac{x^{5}}{5} - \frac{{\color{red}{\int{\frac{1}{x^{4}} d x}}}}{4}=\frac{x^{5}}{5} - \frac{{\color{red}{\int{x^{-4} d x}}}}{4}=\frac{x^{5}}{5} - \frac{{\color{red}{\frac{x^{-4 + 1}}{-4 + 1}}}}{4}=\frac{x^{5}}{5} - \frac{{\color{red}{\left(- \frac{x^{-3}}{3}\right)}}}{4}=\frac{x^{5}}{5} - \frac{{\color{red}{\left(- \frac{1}{3 x^{3}}\right)}}}{4}$$

Dolayısıyla,

$$\int{\left(x^{4} - \frac{1}{4 x^{4}}\right)d x} = \frac{x^{5}}{5} + \frac{1}{12 x^{3}}$$

Sadeleştirin:

$$\int{\left(x^{4} - \frac{1}{4 x^{4}}\right)d x} = \frac{12 x^{8} + 5}{60 x^{3}}$$

İntegrasyon sabitini ekleyin:

$$\int{\left(x^{4} - \frac{1}{4 x^{4}}\right)d x} = \frac{12 x^{8} + 5}{60 x^{3}}+C$$

$$$\int \left(x^{4} - \frac{1}{4 x^{4}}\right)\, dx = \frac{12 x^{8} + 5}{60 x^{3}} + C$$$A