$$$\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2}$$$'nin integrali
İlgili hesap makinesi: Belirli ve Uygunsuz İntegral Hesaplayıcı
Girdiniz
Bulun: $$$\int \frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2}\, d\eta$$$.
Çözüm
Sabit katsayı kuralı $$$\int c f{\left(\eta \right)}\, d\eta = c \int f{\left(\eta \right)}\, d\eta$$$'i $$$c=\frac{\cos{\left(2 \right)}}{2}$$$ ve $$$f{\left(\eta \right)} = \tanh{\left(\eta \right)}$$$ ile uygula:
$${\color{red}{\int{\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2} d \eta}}} = {\color{red}{\left(\frac{\cos{\left(2 \right)} \int{\tanh{\left(\eta \right)} d \eta}}{2}\right)}}$$
Hiperbolik tanjantı $$$\tanh\left(\eta\right)=\frac{\sinh\left(\eta\right)}{\cosh\left(\eta\right)}$$$ olarak yeniden yazın:
$$\frac{\cos{\left(2 \right)} {\color{red}{\int{\tanh{\left(\eta \right)} d \eta}}}}{2} = \frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{\sinh{\left(\eta \right)}}{\cosh{\left(\eta \right)}} d \eta}}}}{2}$$
$$$u=\cosh{\left(\eta \right)}$$$ olsun.
Böylece $$$du=\left(\cosh{\left(\eta \right)}\right)^{\prime }d\eta = \sinh{\left(\eta \right)} d\eta$$$ (adımlar » görülebilir) ve $$$\sinh{\left(\eta \right)} d\eta = du$$$ elde ederiz.
Dolayısıyla,
$$\frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{\sinh{\left(\eta \right)}}{\cosh{\left(\eta \right)}} d \eta}}}}{2} = \frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{1}{u} d u}}}}{2}$$
$$$\frac{1}{u}$$$'nin integrali $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$$\frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{1}{u} d u}}}}{2} = \frac{\cos{\left(2 \right)} {\color{red}{\ln{\left(\left|{u}\right| \right)}}}}{2}$$
Hatırlayın ki $$$u=\cosh{\left(\eta \right)}$$$:
$$\frac{\ln{\left(\left|{{\color{red}{u}}}\right| \right)} \cos{\left(2 \right)}}{2} = \frac{\ln{\left(\left|{{\color{red}{\cosh{\left(\eta \right)}}}}\right| \right)} \cos{\left(2 \right)}}{2}$$
Dolayısıyla,
$$\int{\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2} d \eta} = \frac{\ln{\left(\cosh{\left(\eta \right)} \right)} \cos{\left(2 \right)}}{2}$$
İntegrasyon sabitini ekleyin:
$$\int{\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2} d \eta} = \frac{\ln{\left(\cosh{\left(\eta \right)} \right)} \cos{\left(2 \right)}}{2}+C$$
Cevap
$$$\int \frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2}\, d\eta = \frac{\ln\left(\cosh{\left(\eta \right)}\right) \cos{\left(2 \right)}}{2} + C$$$A