$$$1679616 x^{41}$$$'nin integrali

Bulun: $$$\int 1679616 x^{41}\, dx$$$.

Sabit katsayı kuralı $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$'i $$$c=1679616$$$ ve $$$f{\left(x \right)} = x^{41}$$$ ile uygula:

$${\color{red}{\int{1679616 x^{41} d x}}} = {\color{red}{\left(1679616 \int{x^{41} d x}\right)}}$$

Kuvvet kuralını $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ $$$n=41$$$ ile uygulayın:

$$1679616 {\color{red}{\int{x^{41} d x}}}=1679616 {\color{red}{\frac{x^{1 + 41}}{1 + 41}}}=1679616 {\color{red}{\left(\frac{x^{42}}{42}\right)}}$$

Dolayısıyla,

$$\int{1679616 x^{41} d x} = \frac{279936 x^{42}}{7}$$

İntegrasyon sabitini ekleyin:

$$\int{1679616 x^{41} d x} = \frac{279936 x^{42}}{7}+C$$

$$$\int 1679616 x^{41}\, dx = \frac{279936 x^{42}}{7} + C$$$A