Integralen av $$$- \tan{\left(1 \right)} \tan{\left(x \right)} \sec{\left(x \right)}$$$
Relaterad kalkylator: Kalkylator för bestämda och oegentliga integraler
Din inmatning
Bestäm $$$\int \left(- \tan{\left(1 \right)} \tan{\left(x \right)} \sec{\left(x \right)}\right)\, dx$$$.
Lösning
Tillämpa konstantfaktorregeln $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ med $$$c=- \tan{\left(1 \right)}$$$ och $$$f{\left(x \right)} = \tan{\left(x \right)} \sec{\left(x \right)}$$$:
$${\color{red}{\int{\left(- \tan{\left(1 \right)} \tan{\left(x \right)} \sec{\left(x \right)}\right)d x}}} = {\color{red}{\left(- \tan{\left(1 \right)} \int{\tan{\left(x \right)} \sec{\left(x \right)} d x}\right)}}$$
Integralen av $$$\tan{\left(x \right)} \sec{\left(x \right)}$$$ är $$$\int{\tan{\left(x \right)} \sec{\left(x \right)} d x} = \sec{\left(x \right)}$$$:
$$- \tan{\left(1 \right)} {\color{red}{\int{\tan{\left(x \right)} \sec{\left(x \right)} d x}}} = - \tan{\left(1 \right)} {\color{red}{\sec{\left(x \right)}}}$$
Alltså,
$$\int{\left(- \tan{\left(1 \right)} \tan{\left(x \right)} \sec{\left(x \right)}\right)d x} = - \tan{\left(1 \right)} \sec{\left(x \right)}$$
Lägg till integrationskonstanten:
$$\int{\left(- \tan{\left(1 \right)} \tan{\left(x \right)} \sec{\left(x \right)}\right)d x} = - \tan{\left(1 \right)} \sec{\left(x \right)}+C$$
Svar
$$$\int \left(- \tan{\left(1 \right)} \tan{\left(x \right)} \sec{\left(x \right)}\right)\, dx = - \tan{\left(1 \right)} \sec{\left(x \right)} + C$$$A