Integralen av $$$\sin{\left(x^{2} + y \right)}$$$ med avseende på $$$x$$$

Kalkylatorn beräknar integralen/primitivfunktionen av $$$\sin{\left(x^{2} + y \right)}$$$ med avseende på $$$x$$$, med stegvis lösning.

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Din inmatning

Bestäm $$$\int \sin{\left(x^{2} + y \right)}\, dx$$$.

Lösning

Skriv om integranden:

$${\color{red}{\int{\sin{\left(x^{2} + y \right)} d x}}} = {\color{red}{\int{\left(\sin{\left(x^{2} \right)} \cos{\left(y \right)} + \sin{\left(y \right)} \cos{\left(x^{2} \right)}\right)d x}}}$$

Integrera termvis:

$${\color{red}{\int{\left(\sin{\left(x^{2} \right)} \cos{\left(y \right)} + \sin{\left(y \right)} \cos{\left(x^{2} \right)}\right)d x}}} = {\color{red}{\left(\int{\sin{\left(x^{2} \right)} \cos{\left(y \right)} d x} + \int{\sin{\left(y \right)} \cos{\left(x^{2} \right)} d x}\right)}}$$

Tillämpa konstantfaktorregeln $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ med $$$c=\cos{\left(y \right)}$$$ och $$$f{\left(x \right)} = \sin{\left(x^{2} \right)}$$$:

$$\int{\sin{\left(y \right)} \cos{\left(x^{2} \right)} d x} + {\color{red}{\int{\sin{\left(x^{2} \right)} \cos{\left(y \right)} d x}}} = \int{\sin{\left(y \right)} \cos{\left(x^{2} \right)} d x} + {\color{red}{\cos{\left(y \right)} \int{\sin{\left(x^{2} \right)} d x}}}$$

Denna integral (Fresnels sinusintegral) har ingen sluten form:

$$\cos{\left(y \right)} {\color{red}{\int{\sin{\left(x^{2} \right)} d x}}} + \int{\sin{\left(y \right)} \cos{\left(x^{2} \right)} d x} = \cos{\left(y \right)} {\color{red}{\left(\frac{\sqrt{2} \sqrt{\pi} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2}\right)}} + \int{\sin{\left(y \right)} \cos{\left(x^{2} \right)} d x}$$

Tillämpa konstantfaktorregeln $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ med $$$c=\sin{\left(y \right)}$$$ och $$$f{\left(x \right)} = \cos{\left(x^{2} \right)}$$$:

$$\frac{\sqrt{2} \sqrt{\pi} \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2} + {\color{red}{\int{\sin{\left(y \right)} \cos{\left(x^{2} \right)} d x}}} = \frac{\sqrt{2} \sqrt{\pi} \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2} + {\color{red}{\sin{\left(y \right)} \int{\cos{\left(x^{2} \right)} d x}}}$$

Denna integral (Fresnels cosinusintegral) har ingen sluten form:

$$\sin{\left(y \right)} {\color{red}{\int{\cos{\left(x^{2} \right)} d x}}} + \frac{\sqrt{2} \sqrt{\pi} \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2} = \sin{\left(y \right)} {\color{red}{\left(\frac{\sqrt{2} \sqrt{\pi} C\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2}\right)}} + \frac{\sqrt{2} \sqrt{\pi} \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2}$$

Alltså,

$$\int{\sin{\left(x^{2} + y \right)} d x} = \frac{\sqrt{2} \sqrt{\pi} \sin{\left(y \right)} C\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2} + \frac{\sqrt{2} \sqrt{\pi} \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)}{2}$$

Förenkla:

$$\int{\sin{\left(x^{2} + y \right)} d x} = \frac{\sqrt{2} \sqrt{\pi} \left(\sin{\left(y \right)} C\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right) + \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)\right)}{2}$$

Lägg till integrationskonstanten:

$$\int{\sin{\left(x^{2} + y \right)} d x} = \frac{\sqrt{2} \sqrt{\pi} \left(\sin{\left(y \right)} C\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right) + \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)\right)}{2}+C$$

Svar

$$$\int \sin{\left(x^{2} + y \right)}\, dx = \frac{\sqrt{2} \sqrt{\pi} \left(\sin{\left(y \right)} C\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right) + \cos{\left(y \right)} S\left(\frac{\sqrt{2} x}{\sqrt{\pi}}\right)\right)}{2} + C$$$A