Integralen av $$$e^{x} \tan^{x}{\left(e \right)}$$$
Relaterad kalkylator: Kalkylator för bestämda och oegentliga integraler
Din inmatning
Bestäm $$$\int e^{x} \tan^{x}{\left(e \right)}\, dx$$$.
Lösning
Inmatningen skrivs om: $$$\int{e^{x} \tan^{x}{\left(e \right)} d x}=\int{\left(e \tan{\left(e \right)}\right)^{x} d x}$$$.
Apply the exponential rule $$$\int{a^{x} d x} = \frac{a^{x}}{\ln{\left(a \right)}}$$$ with $$$a=e \tan{\left(e \right)}$$$:
$${\color{red}{\int{\left(e \tan{\left(e \right)}\right)^{x} d x}}} = {\color{red}{\frac{\left(e \tan{\left(e \right)}\right)^{x}}{\ln{\left(e \tan{\left(e \right)} \right)}}}}$$
Alltså,
$$\int{\left(e \tan{\left(e \right)}\right)^{x} d x} = \frac{\left(e \tan{\left(e \right)}\right)^{x}}{\ln{\left(e \tan{\left(e \right)} \right)}}$$
Förenkla:
$$\int{\left(e \tan{\left(e \right)}\right)^{x} d x} = \frac{e^{x} \tan^{x}{\left(e \right)}}{\ln{\left(- \tan{\left(e \right)} \right)} + 1 + i \pi}$$
Lägg till integrationskonstanten:
$$\int{\left(e \tan{\left(e \right)}\right)^{x} d x} = \frac{e^{x} \tan^{x}{\left(e \right)}}{\ln{\left(- \tan{\left(e \right)} \right)} + 1 + i \pi}+C$$
Svar
$$$\int e^{x} \tan^{x}{\left(e \right)}\, dx = \frac{e^{x} \tan^{x}{\left(e \right)}}{\ln\left(- \tan{\left(e \right)}\right) + 1 + i \pi} + C$$$A