Integralen av $$$\cot^{3}{\left(\frac{x}{5} \right)} \csc^{3}{\left(\frac{x}{5} \right)}$$$
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Din inmatning
Bestäm $$$\int \cot^{3}{\left(\frac{x}{5} \right)} \csc^{3}{\left(\frac{x}{5} \right)}\, dx$$$.
Lösning
Låt $$$u=\frac{x}{5}$$$ vara.
Då $$$du=\left(\frac{x}{5}\right)^{\prime }dx = \frac{dx}{5}$$$ (stegen kan ses »), och vi har att $$$dx = 5 du$$$.
Integralen blir
$${\color{red}{\int{\cot^{3}{\left(\frac{x}{5} \right)} \csc^{3}{\left(\frac{x}{5} \right)} d x}}} = {\color{red}{\int{5 \cot^{3}{\left(u \right)} \csc^{3}{\left(u \right)} d u}}}$$
Tillämpa konstantfaktorregeln $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ med $$$c=5$$$ och $$$f{\left(u \right)} = \cot^{3}{\left(u \right)} \csc^{3}{\left(u \right)}$$$:
$${\color{red}{\int{5 \cot^{3}{\left(u \right)} \csc^{3}{\left(u \right)} d u}}} = {\color{red}{\left(5 \int{\cot^{3}{\left(u \right)} \csc^{3}{\left(u \right)} d u}\right)}}$$
Bryt ut en cotangens och skriv allt annat i termer av kosekanten, med formeln $$$\cot^2\left( u \right)=\csc^2\left( u \right)-1$$$:
$$5 {\color{red}{\int{\cot^{3}{\left(u \right)} \csc^{3}{\left(u \right)} d u}}} = 5 {\color{red}{\int{\left(\csc^{2}{\left(u \right)} - 1\right) \cot{\left(u \right)} \csc^{3}{\left(u \right)} d u}}}$$
Låt $$$v=\csc{\left(u \right)}$$$ vara.
Då $$$dv=\left(\csc{\left(u \right)}\right)^{\prime }du = - \cot{\left(u \right)} \csc{\left(u \right)} du$$$ (stegen kan ses »), och vi har att $$$\cot{\left(u \right)} \csc{\left(u \right)} du = - dv$$$.
Integralen kan omskrivas som
$$5 {\color{red}{\int{\left(\csc^{2}{\left(u \right)} - 1\right) \cot{\left(u \right)} \csc^{3}{\left(u \right)} d u}}} = 5 {\color{red}{\int{\left(- v^{2} \left(v^{2} - 1\right)\right)d v}}}$$
Tillämpa konstantfaktorregeln $$$\int c f{\left(v \right)}\, dv = c \int f{\left(v \right)}\, dv$$$ med $$$c=-1$$$ och $$$f{\left(v \right)} = v^{2} \left(v^{2} - 1\right)$$$:
$$5 {\color{red}{\int{\left(- v^{2} \left(v^{2} - 1\right)\right)d v}}} = 5 {\color{red}{\left(- \int{v^{2} \left(v^{2} - 1\right) d v}\right)}}$$
Expand the expression:
$$- 5 {\color{red}{\int{v^{2} \left(v^{2} - 1\right) d v}}} = - 5 {\color{red}{\int{\left(v^{4} - v^{2}\right)d v}}}$$
Integrera termvis:
$$- 5 {\color{red}{\int{\left(v^{4} - v^{2}\right)d v}}} = - 5 {\color{red}{\left(- \int{v^{2} d v} + \int{v^{4} d v}\right)}}$$
Tillämpa potensregeln $$$\int v^{n}\, dv = \frac{v^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ med $$$n=4$$$:
$$5 \int{v^{2} d v} - 5 {\color{red}{\int{v^{4} d v}}}=5 \int{v^{2} d v} - 5 {\color{red}{\frac{v^{1 + 4}}{1 + 4}}}=5 \int{v^{2} d v} - 5 {\color{red}{\left(\frac{v^{5}}{5}\right)}}$$
Tillämpa potensregeln $$$\int v^{n}\, dv = \frac{v^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ med $$$n=2$$$:
$$- v^{5} + 5 {\color{red}{\int{v^{2} d v}}}=- v^{5} + 5 {\color{red}{\frac{v^{1 + 2}}{1 + 2}}}=- v^{5} + 5 {\color{red}{\left(\frac{v^{3}}{3}\right)}}$$
Kom ihåg att $$$v=\csc{\left(u \right)}$$$:
$$\frac{5 {\color{red}{v}}^{3}}{3} - {\color{red}{v}}^{5} = \frac{5 {\color{red}{\csc{\left(u \right)}}}^{3}}{3} - {\color{red}{\csc{\left(u \right)}}}^{5}$$
Kom ihåg att $$$u=\frac{x}{5}$$$:
$$\frac{5 \csc^{3}{\left({\color{red}{u}} \right)}}{3} - \csc^{5}{\left({\color{red}{u}} \right)} = \frac{5 \csc^{3}{\left({\color{red}{\left(\frac{x}{5}\right)}} \right)}}{3} - \csc^{5}{\left({\color{red}{\left(\frac{x}{5}\right)}} \right)}$$
Alltså,
$$\int{\cot^{3}{\left(\frac{x}{5} \right)} \csc^{3}{\left(\frac{x}{5} \right)} d x} = - \csc^{5}{\left(\frac{x}{5} \right)} + \frac{5 \csc^{3}{\left(\frac{x}{5} \right)}}{3}$$
Förenkla:
$$\int{\cot^{3}{\left(\frac{x}{5} \right)} \csc^{3}{\left(\frac{x}{5} \right)} d x} = \left(\frac{5}{3} - \csc^{2}{\left(\frac{x}{5} \right)}\right) \csc^{3}{\left(\frac{x}{5} \right)}$$
Lägg till integrationskonstanten:
$$\int{\cot^{3}{\left(\frac{x}{5} \right)} \csc^{3}{\left(\frac{x}{5} \right)} d x} = \left(\frac{5}{3} - \csc^{2}{\left(\frac{x}{5} \right)}\right) \csc^{3}{\left(\frac{x}{5} \right)}+C$$
Svar
$$$\int \cot^{3}{\left(\frac{x}{5} \right)} \csc^{3}{\left(\frac{x}{5} \right)}\, dx = \left(\frac{5}{3} - \csc^{2}{\left(\frac{x}{5} \right)}\right) \csc^{3}{\left(\frac{x}{5} \right)} + C$$$A