Integralen av $$$\frac{1}{44 x^{2}}$$$

Bestäm $$$\int \frac{1}{44 x^{2}}\, dx$$$.

Tillämpa konstantfaktorregeln $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ med $$$c=\frac{1}{44}$$$ och $$$f{\left(x \right)} = \frac{1}{x^{2}}$$$:

$${\color{red}{\int{\frac{1}{44 x^{2}} d x}}} = {\color{red}{\left(\frac{\int{\frac{1}{x^{2}} d x}}{44}\right)}}$$

Tillämpa potensregeln $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ med $$$n=-2$$$:

$$\frac{{\color{red}{\int{\frac{1}{x^{2}} d x}}}}{44}=\frac{{\color{red}{\int{x^{-2} d x}}}}{44}=\frac{{\color{red}{\frac{x^{-2 + 1}}{-2 + 1}}}}{44}=\frac{{\color{red}{\left(- x^{-1}\right)}}}{44}=\frac{{\color{red}{\left(- \frac{1}{x}\right)}}}{44}$$

Alltså,

$$\int{\frac{1}{44 x^{2}} d x} = - \frac{1}{44 x}$$

Lägg till integrationskonstanten:

$$\int{\frac{1}{44 x^{2}} d x} = - \frac{1}{44 x}+C$$

$$$\int \frac{1}{44 x^{2}}\, dx = - \frac{1}{44 x} + C$$$A