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  1. Beranda
  2. Kalkulator
  3. Kalkulator: Aljabar Linear
  4. Kalkulator Aljabar Linear

$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\1 & 2 & 3\end{array}\right]\cdot \left[\begin{array}{ccc}- \frac{1}{2} & 0 & \frac{1}{2}\\5 & -1 & -1\\- \frac{7}{2} & 1 & \frac{1}{2}\end{array}\right]$$$

Kalkulator akan mengalikan matriks $$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\1 & 2 & 3\end{array}\right]$$$ berukuran $$$3$$$x$$$3$$$ dengan matriks $$$\left[\begin{array}{ccc}- \frac{1}{2} & 0 & \frac{1}{2}\\5 & -1 & -1\\- \frac{7}{2} & 1 & \frac{1}{2}\end{array}\right]$$$ berukuran $$$3$$$x$$$3$$$, dengan langkah-langkah yang ditampilkan.

Kalkulator terkait: Kalkulator Matriks

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A
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A

Jika kalkulator tidak menghitung sesuatu atau Anda menemukan kesalahan, atau Anda memiliki saran/masukan, silakan hubungi kami.

Masukan Anda

Hitung $$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\1 & 2 & 3\end{array}\right]\cdot \left[\begin{array}{ccc}- \frac{1}{2} & 0 & \frac{1}{2}\\5 & -1 & -1\\- \frac{7}{2} & 1 & \frac{1}{2}\end{array}\right].$$$

Solusi

$$$\left[\begin{array}{ccc}{\color{OrangeRed}4} & {\color{DarkMagenta}5} & {\color{GoldenRod}7}\\{\color{Chocolate}2} & {\color{BlueViolet}1} & {\color{Violet}0}\\{\color{Purple}1} & {\color{DarkCyan}2} & {\color{Chartreuse}3}\end{array}\right]\cdot \left[\begin{array}{ccc}{\color{Chocolate}- \frac{1}{2}} & {\color{Brown}0} & {\color{Crimson}\frac{1}{2}}\\{\color{Blue}5} & {\color{OrangeRed}-1} & {\color{DarkMagenta}-1}\\{\color{Violet}- \frac{7}{2}} & {\color{BlueViolet}1} & {\color{GoldenRod}\frac{1}{2}}\end{array}\right] = \left[\begin{array}{ccc}{\color{OrangeRed}\left(4\right)}\cdot {\color{Chocolate}\left(- \frac{1}{2}\right)} + {\color{DarkMagenta}\left(5\right)}\cdot {\color{Blue}\left(5\right)} + {\color{GoldenRod}\left(7\right)}\cdot {\color{Violet}\left(- \frac{7}{2}\right)} & {\color{OrangeRed}\left(4\right)}\cdot {\color{Brown}\left(0\right)} + {\color{DarkMagenta}\left(5\right)}\cdot {\color{OrangeRed}\left(-1\right)} + {\color{GoldenRod}\left(7\right)}\cdot {\color{BlueViolet}\left(1\right)} & {\color{OrangeRed}\left(4\right)}\cdot {\color{Crimson}\left(\frac{1}{2}\right)} + {\color{DarkMagenta}\left(5\right)}\cdot {\color{DarkMagenta}\left(-1\right)} + {\color{GoldenRod}\left(7\right)}\cdot {\color{GoldenRod}\left(\frac{1}{2}\right)}\\{\color{Chocolate}\left(2\right)}\cdot {\color{Chocolate}\left(- \frac{1}{2}\right)} + {\color{BlueViolet}\left(1\right)}\cdot {\color{Blue}\left(5\right)} + {\color{Violet}\left(0\right)}\cdot {\color{Violet}\left(- \frac{7}{2}\right)} & {\color{Chocolate}\left(2\right)}\cdot {\color{Brown}\left(0\right)} + {\color{BlueViolet}\left(1\right)}\cdot {\color{OrangeRed}\left(-1\right)} + {\color{Violet}\left(0\right)}\cdot {\color{BlueViolet}\left(1\right)} & {\color{Chocolate}\left(2\right)}\cdot {\color{Crimson}\left(\frac{1}{2}\right)} + {\color{BlueViolet}\left(1\right)}\cdot {\color{DarkMagenta}\left(-1\right)} + {\color{Violet}\left(0\right)}\cdot {\color{GoldenRod}\left(\frac{1}{2}\right)}\\{\color{Purple}\left(1\right)}\cdot {\color{Chocolate}\left(- \frac{1}{2}\right)} + {\color{DarkCyan}\left(2\right)}\cdot {\color{Blue}\left(5\right)} + {\color{Chartreuse}\left(3\right)}\cdot {\color{Violet}\left(- \frac{7}{2}\right)} & {\color{Purple}\left(1\right)}\cdot {\color{Brown}\left(0\right)} + {\color{DarkCyan}\left(2\right)}\cdot {\color{OrangeRed}\left(-1\right)} + {\color{Chartreuse}\left(3\right)}\cdot {\color{BlueViolet}\left(1\right)} & {\color{Purple}\left(1\right)}\cdot {\color{Crimson}\left(\frac{1}{2}\right)} + {\color{DarkCyan}\left(2\right)}\cdot {\color{DarkMagenta}\left(-1\right)} + {\color{Chartreuse}\left(3\right)}\cdot {\color{GoldenRod}\left(\frac{1}{2}\right)}\end{array}\right] = \left[\begin{array}{ccc}- \frac{3}{2} & 2 & \frac{1}{2}\\4 & -1 & 0\\-1 & 1 & 0\end{array}\right]$$$

Jawaban

$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\1 & 2 & 3\end{array}\right]\cdot \left[\begin{array}{ccc}- \frac{1}{2} & 0 & \frac{1}{2}\\5 & -1 & -1\\- \frac{7}{2} & 1 & \frac{1}{2}\end{array}\right] = \left[\begin{array}{ccc}- \frac{3}{2} & 2 & \frac{1}{2}\\4 & -1 & 0\\-1 & 1 & 0\end{array}\right] = \left[\begin{array}{ccc}-1.5 & 2 & 0.5\\4 & -1 & 0\\-1 & 1 & 0\end{array}\right]$$$A