Integral dari $$$p y^{2} \left(p^{2} + 1\right)^{2}$$$ terhadap $$$y$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int p y^{2} \left(p^{2} + 1\right)^{2}\, dy$$$.
Solusi
Terapkan aturan pengali konstanta $$$\int c f{\left(y \right)}\, dy = c \int f{\left(y \right)}\, dy$$$ dengan $$$c=p \left(p^{2} + 1\right)^{2}$$$ dan $$$f{\left(y \right)} = y^{2}$$$:
$${\color{red}{\int{p y^{2} \left(p^{2} + 1\right)^{2} d y}}} = {\color{red}{p \left(p^{2} + 1\right)^{2} \int{y^{2} d y}}}$$
Terapkan aturan pangkat $$$\int y^{n}\, dy = \frac{y^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ dengan $$$n=2$$$:
$$p \left(p^{2} + 1\right)^{2} {\color{red}{\int{y^{2} d y}}}=p \left(p^{2} + 1\right)^{2} {\color{red}{\frac{y^{1 + 2}}{1 + 2}}}=p \left(p^{2} + 1\right)^{2} {\color{red}{\left(\frac{y^{3}}{3}\right)}}$$
Oleh karena itu,
$$\int{p y^{2} \left(p^{2} + 1\right)^{2} d y} = \frac{p y^{3} \left(p^{2} + 1\right)^{2}}{3}$$
Tambahkan konstanta integrasi:
$$\int{p y^{2} \left(p^{2} + 1\right)^{2} d y} = \frac{p y^{3} \left(p^{2} + 1\right)^{2}}{3}+C$$
Jawaban
$$$\int p y^{2} \left(p^{2} + 1\right)^{2}\, dy = \frac{p y^{3} \left(p^{2} + 1\right)^{2}}{3} + C$$$A