Integral dari $$$- 2 x + 10 e$$$

Temukan $$$\int \left(- 2 x + 10 e\right)\, dx$$$.

Integralkan suku demi suku:

$${\color{red}{\int{\left(- 2 x + 10 e\right)d x}}} = {\color{red}{\left(\int{10 e d x} - \int{2 x d x}\right)}}$$

Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=2$$$ dan $$$f{\left(x \right)} = x$$$:

$$\int{10 e d x} - {\color{red}{\int{2 x d x}}} = \int{10 e d x} - {\color{red}{\left(2 \int{x d x}\right)}}$$

Terapkan aturan pangkat $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ dengan $$$n=1$$$:

$$\int{10 e d x} - 2 {\color{red}{\int{x d x}}}=\int{10 e d x} - 2 {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=\int{10 e d x} - 2 {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Terapkan aturan konstanta $$$\int c\, dx = c x$$$ dengan $$$c=10 e$$$:

$$- x^{2} + {\color{red}{\int{10 e d x}}} = - x^{2} + {\color{red}{\left(10 e x\right)}}$$

Oleh karena itu,

$$\int{\left(- 2 x + 10 e\right)d x} = - x^{2} + 10 e x$$

Sederhanakan:

$$\int{\left(- 2 x + 10 e\right)d x} = x \left(- x + 10 e\right)$$

Tambahkan konstanta integrasi:

$$\int{\left(- 2 x + 10 e\right)d x} = x \left(- x + 10 e\right)+C$$

$$$\int \left(- 2 x + 10 e\right)\, dx = x \left(- x + 10 e\right) + C$$$A