Integral dari $$$- 2 \sin{\left(x \right)} \cos{\left(2 x \right)}$$$

Temukan $$$\int \left(- 2 \sin{\left(x \right)} \cos{\left(2 x \right)}\right)\, dx$$$.

Tulis ulang $$$\sin\left(x \right)\cos\left(2 x \right)$$$ menggunakan rumus $$$\sin\left(\alpha \right)\cos\left(\beta \right)=\frac{1}{2} \sin\left(\alpha-\beta \right)+\frac{1}{2} \sin\left(\alpha+\beta \right)$$$ dengan $$$\alpha=x$$$ dan $$$\beta=2 x$$$:

$${\color{red}{\int{\left(- 2 \sin{\left(x \right)} \cos{\left(2 x \right)}\right)d x}}} = {\color{red}{\int{\left(\sin{\left(x \right)} - \sin{\left(3 x \right)}\right)d x}}}$$

Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=\frac{1}{2}$$$ dan $$$f{\left(x \right)} = 2 \sin{\left(x \right)} - 2 \sin{\left(3 x \right)}$$$:

$${\color{red}{\int{\left(\sin{\left(x \right)} - \sin{\left(3 x \right)}\right)d x}}} = {\color{red}{\left(\frac{\int{\left(2 \sin{\left(x \right)} - 2 \sin{\left(3 x \right)}\right)d x}}{2}\right)}}$$

Integralkan suku demi suku:

$$\frac{{\color{red}{\int{\left(2 \sin{\left(x \right)} - 2 \sin{\left(3 x \right)}\right)d x}}}}{2} = \frac{{\color{red}{\left(\int{2 \sin{\left(x \right)} d x} - \int{2 \sin{\left(3 x \right)} d x}\right)}}}{2}$$

Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=2$$$ dan $$$f{\left(x \right)} = \sin{\left(3 x \right)}$$$:

$$\frac{\int{2 \sin{\left(x \right)} d x}}{2} - \frac{{\color{red}{\int{2 \sin{\left(3 x \right)} d x}}}}{2} = \frac{\int{2 \sin{\left(x \right)} d x}}{2} - \frac{{\color{red}{\left(2 \int{\sin{\left(3 x \right)} d x}\right)}}}{2}$$

Misalkan $$$u=3 x$$$.

Kemudian $$$du=\left(3 x\right)^{\prime }dx = 3 dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dx = \frac{du}{3}$$$.

Oleh karena itu,

$$\frac{\int{2 \sin{\left(x \right)} d x}}{2} - {\color{red}{\int{\sin{\left(3 x \right)} d x}}} = \frac{\int{2 \sin{\left(x \right)} d x}}{2} - {\color{red}{\int{\frac{\sin{\left(u \right)}}{3} d u}}}$$

Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{3}$$$ dan $$$f{\left(u \right)} = \sin{\left(u \right)}$$$:

$$\frac{\int{2 \sin{\left(x \right)} d x}}{2} - {\color{red}{\int{\frac{\sin{\left(u \right)}}{3} d u}}} = \frac{\int{2 \sin{\left(x \right)} d x}}{2} - {\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{3}\right)}}$$

Integral dari sinus adalah $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:

$$\frac{\int{2 \sin{\left(x \right)} d x}}{2} - \frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{3} = \frac{\int{2 \sin{\left(x \right)} d x}}{2} - \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{3}$$

Ingat bahwa $$$u=3 x$$$:

$$\frac{\int{2 \sin{\left(x \right)} d x}}{2} + \frac{\cos{\left({\color{red}{u}} \right)}}{3} = \frac{\int{2 \sin{\left(x \right)} d x}}{2} + \frac{\cos{\left({\color{red}{\left(3 x\right)}} \right)}}{3}$$

Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=2$$$ dan $$$f{\left(x \right)} = \sin{\left(x \right)}$$$:

$$\frac{\cos{\left(3 x \right)}}{3} + \frac{{\color{red}{\int{2 \sin{\left(x \right)} d x}}}}{2} = \frac{\cos{\left(3 x \right)}}{3} + \frac{{\color{red}{\left(2 \int{\sin{\left(x \right)} d x}\right)}}}{2}$$

Integral dari sinus adalah $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:

$$\frac{\cos{\left(3 x \right)}}{3} + {\color{red}{\int{\sin{\left(x \right)} d x}}} = \frac{\cos{\left(3 x \right)}}{3} + {\color{red}{\left(- \cos{\left(x \right)}\right)}}$$

Oleh karena itu,

$$\int{\left(- 2 \sin{\left(x \right)} \cos{\left(2 x \right)}\right)d x} = - \cos{\left(x \right)} + \frac{\cos{\left(3 x \right)}}{3}$$

Tambahkan konstanta integrasi:

$$\int{\left(- 2 \sin{\left(x \right)} \cos{\left(2 x \right)}\right)d x} = - \cos{\left(x \right)} + \frac{\cos{\left(3 x \right)}}{3}+C$$

$$$\int \left(- 2 \sin{\left(x \right)} \cos{\left(2 x \right)}\right)\, dx = \left(- \cos{\left(x \right)} + \frac{\cos{\left(3 x \right)}}{3}\right) + C$$$A