Integral dari $$$\sec^{2}{\left(\frac{x}{2} \right)}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \sec^{2}{\left(\frac{x}{2} \right)}\, dx$$$.
Solusi
Misalkan $$$u=\frac{x}{2}$$$.
Kemudian $$$du=\left(\frac{x}{2}\right)^{\prime }dx = \frac{dx}{2}$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dx = 2 du$$$.
Oleh karena itu,
$${\color{red}{\int{\sec^{2}{\left(\frac{x}{2} \right)} d x}}} = {\color{red}{\int{2 \sec^{2}{\left(u \right)} d u}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=2$$$ dan $$$f{\left(u \right)} = \sec^{2}{\left(u \right)}$$$:
$${\color{red}{\int{2 \sec^{2}{\left(u \right)} d u}}} = {\color{red}{\left(2 \int{\sec^{2}{\left(u \right)} d u}\right)}}$$
Integral dari $$$\sec^{2}{\left(u \right)}$$$ adalah $$$\int{\sec^{2}{\left(u \right)} d u} = \tan{\left(u \right)}$$$:
$$2 {\color{red}{\int{\sec^{2}{\left(u \right)} d u}}} = 2 {\color{red}{\tan{\left(u \right)}}}$$
Ingat bahwa $$$u=\frac{x}{2}$$$:
$$2 \tan{\left({\color{red}{u}} \right)} = 2 \tan{\left({\color{red}{\left(\frac{x}{2}\right)}} \right)}$$
Oleh karena itu,
$$\int{\sec^{2}{\left(\frac{x}{2} \right)} d x} = 2 \tan{\left(\frac{x}{2} \right)}$$
Tambahkan konstanta integrasi:
$$\int{\sec^{2}{\left(\frac{x}{2} \right)} d x} = 2 \tan{\left(\frac{x}{2} \right)}+C$$
Jawaban
$$$\int \sec^{2}{\left(\frac{x}{2} \right)}\, dx = 2 \tan{\left(\frac{x}{2} \right)} + C$$$A