Integral dari $$$\cos{\left(2 t \right)}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \cos{\left(2 t \right)}\, dt$$$.
Solusi
Misalkan $$$u=2 t$$$.
Kemudian $$$du=\left(2 t\right)^{\prime }dt = 2 dt$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dt = \frac{du}{2}$$$.
Jadi,
$${\color{red}{\int{\cos{\left(2 t \right)} d t}}} = {\color{red}{\int{\frac{\cos{\left(u \right)}}{2} d u}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{2}$$$ dan $$$f{\left(u \right)} = \cos{\left(u \right)}$$$:
$${\color{red}{\int{\frac{\cos{\left(u \right)}}{2} d u}}} = {\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{2}\right)}}$$
Integral dari kosinus adalah $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:
$$\frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{2} = \frac{{\color{red}{\sin{\left(u \right)}}}}{2}$$
Ingat bahwa $$$u=2 t$$$:
$$\frac{\sin{\left({\color{red}{u}} \right)}}{2} = \frac{\sin{\left({\color{red}{\left(2 t\right)}} \right)}}{2}$$
Oleh karena itu,
$$\int{\cos{\left(2 t \right)} d t} = \frac{\sin{\left(2 t \right)}}{2}$$
Tambahkan konstanta integrasi:
$$\int{\cos{\left(2 t \right)} d t} = \frac{\sin{\left(2 t \right)}}{2}+C$$
Jawaban
$$$\int \cos{\left(2 t \right)}\, dt = \frac{\sin{\left(2 t \right)}}{2} + C$$$A