Integral dari $$$\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2}\, d\eta$$$.
Solusi
Terapkan aturan pengali konstanta $$$\int c f{\left(\eta \right)}\, d\eta = c \int f{\left(\eta \right)}\, d\eta$$$ dengan $$$c=\frac{\cos{\left(2 \right)}}{2}$$$ dan $$$f{\left(\eta \right)} = \tanh{\left(\eta \right)}$$$:
$${\color{red}{\int{\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2} d \eta}}} = {\color{red}{\left(\frac{\cos{\left(2 \right)} \int{\tanh{\left(\eta \right)} d \eta}}{2}\right)}}$$
Tulis ulang tangen hiperbolik sebagai $$$\tanh\left(\eta\right)=\frac{\sinh\left(\eta\right)}{\cosh\left(\eta\right)}$$$:
$$\frac{\cos{\left(2 \right)} {\color{red}{\int{\tanh{\left(\eta \right)} d \eta}}}}{2} = \frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{\sinh{\left(\eta \right)}}{\cosh{\left(\eta \right)}} d \eta}}}}{2}$$
Misalkan $$$u=\cosh{\left(\eta \right)}$$$.
Kemudian $$$du=\left(\cosh{\left(\eta \right)}\right)^{\prime }d\eta = \sinh{\left(\eta \right)} d\eta$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$\sinh{\left(\eta \right)} d\eta = du$$$.
Integral tersebut dapat ditulis ulang sebagai
$$\frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{\sinh{\left(\eta \right)}}{\cosh{\left(\eta \right)}} d \eta}}}}{2} = \frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{1}{u} d u}}}}{2}$$
Integral dari $$$\frac{1}{u}$$$ adalah $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$$\frac{\cos{\left(2 \right)} {\color{red}{\int{\frac{1}{u} d u}}}}{2} = \frac{\cos{\left(2 \right)} {\color{red}{\ln{\left(\left|{u}\right| \right)}}}}{2}$$
Ingat bahwa $$$u=\cosh{\left(\eta \right)}$$$:
$$\frac{\ln{\left(\left|{{\color{red}{u}}}\right| \right)} \cos{\left(2 \right)}}{2} = \frac{\ln{\left(\left|{{\color{red}{\cosh{\left(\eta \right)}}}}\right| \right)} \cos{\left(2 \right)}}{2}$$
Oleh karena itu,
$$\int{\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2} d \eta} = \frac{\ln{\left(\cosh{\left(\eta \right)} \right)} \cos{\left(2 \right)}}{2}$$
Tambahkan konstanta integrasi:
$$\int{\frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2} d \eta} = \frac{\ln{\left(\cosh{\left(\eta \right)} \right)} \cos{\left(2 \right)}}{2}+C$$
Jawaban
$$$\int \frac{\cos{\left(2 \right)} \tanh{\left(\eta \right)}}{2}\, d\eta = \frac{\ln\left(\cosh{\left(\eta \right)}\right) \cos{\left(2 \right)}}{2} + C$$$A