Integral dari $$$4 \sin^{3}{\left(7 x \right)} \cos{\left(7 x \right)}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int 4 \sin^{3}{\left(7 x \right)} \cos{\left(7 x \right)}\, dx$$$.
Solusi
Terapkan rumus reduksi pangkat $$$\sin^{3}{\left(\alpha \right)} = \frac{3 \sin{\left(\alpha \right)}}{4} - \frac{\sin{\left(3 \alpha \right)}}{4}$$$ dengan $$$\alpha=7 x$$$:
$${\color{red}{\int{4 \sin^{3}{\left(7 x \right)} \cos{\left(7 x \right)} d x}}} = {\color{red}{\int{\left(3 \sin{\left(7 x \right)} - \sin{\left(21 x \right)}\right) \cos{\left(7 x \right)} d x}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=\frac{1}{4}$$$ dan $$$f{\left(x \right)} = 4 \left(3 \sin{\left(7 x \right)} - \sin{\left(21 x \right)}\right) \cos{\left(7 x \right)}$$$:
$${\color{red}{\int{\left(3 \sin{\left(7 x \right)} - \sin{\left(21 x \right)}\right) \cos{\left(7 x \right)} d x}}} = {\color{red}{\left(\frac{\int{4 \left(3 \sin{\left(7 x \right)} - \sin{\left(21 x \right)}\right) \cos{\left(7 x \right)} d x}}{4}\right)}}$$
Expand the expression:
$$\frac{{\color{red}{\int{4 \left(3 \sin{\left(7 x \right)} - \sin{\left(21 x \right)}\right) \cos{\left(7 x \right)} d x}}}}{4} = \frac{{\color{red}{\int{\left(12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} - 4 \sin{\left(21 x \right)} \cos{\left(7 x \right)}\right)d x}}}}{4}$$
Integralkan suku demi suku:
$$\frac{{\color{red}{\int{\left(12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} - 4 \sin{\left(21 x \right)} \cos{\left(7 x \right)}\right)d x}}}}{4} = \frac{{\color{red}{\left(\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x} - \int{4 \sin{\left(21 x \right)} \cos{\left(7 x \right)} d x}\right)}}}{4}$$
Tulis ulang $$$\sin\left(21 x \right)\cos\left(7 x \right)$$$ menggunakan rumus $$$\sin\left(\alpha \right)\cos\left(\beta \right)=\frac{1}{2} \sin\left(\alpha-\beta \right)+\frac{1}{2} \sin\left(\alpha+\beta \right)$$$ dengan $$$\alpha=21 x$$$ dan $$$\beta=7 x$$$:
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{4 \sin{\left(21 x \right)} \cos{\left(7 x \right)} d x}}}}{4} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{\left(2 \sin{\left(14 x \right)} + 2 \sin{\left(28 x \right)}\right)d x}}}}{4}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=\frac{1}{2}$$$ dan $$$f{\left(x \right)} = 4 \sin{\left(14 x \right)} + 4 \sin{\left(28 x \right)}$$$:
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{\left(2 \sin{\left(14 x \right)} + 2 \sin{\left(28 x \right)}\right)d x}}}}{4} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\left(\frac{\int{\left(4 \sin{\left(14 x \right)} + 4 \sin{\left(28 x \right)}\right)d x}}{2}\right)}}}{4}$$
Integralkan suku demi suku:
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{\left(4 \sin{\left(14 x \right)} + 4 \sin{\left(28 x \right)}\right)d x}}}}{8} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\left(\int{4 \sin{\left(14 x \right)} d x} + \int{4 \sin{\left(28 x \right)} d x}\right)}}}{8}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=4$$$ dan $$$f{\left(x \right)} = \sin{\left(14 x \right)}$$$:
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\int{4 \sin{\left(14 x \right)} d x}}}}{8} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\left(4 \int{\sin{\left(14 x \right)} d x}\right)}}}{8}$$
Misalkan $$$u=14 x$$$.
Kemudian $$$du=\left(14 x\right)^{\prime }dx = 14 dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dx = \frac{du}{14}$$$.
Oleh karena itu,
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\int{\sin{\left(14 x \right)} d x}}}}{2} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{14} d u}}}}{2}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{14}$$$ dan $$$f{\left(u \right)} = \sin{\left(u \right)}$$$:
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{14} d u}}}}{2} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{14}\right)}}}{2}$$
Integral dari sinus adalah $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{28} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} - \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{28}$$
Ingat bahwa $$$u=14 x$$$:
$$\frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} + \frac{\cos{\left({\color{red}{u}} \right)}}{28} = \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{\int{4 \sin{\left(28 x \right)} d x}}{8} + \frac{\cos{\left({\color{red}{\left(14 x\right)}} \right)}}{28}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=4$$$ dan $$$f{\left(x \right)} = \sin{\left(28 x \right)}$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{4 \sin{\left(28 x \right)} d x}}}}{8} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\left(4 \int{\sin{\left(28 x \right)} d x}\right)}}}{8}$$
Misalkan $$$u=28 x$$$.
Kemudian $$$du=\left(28 x\right)^{\prime }dx = 28 dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dx = \frac{du}{28}$$$.
Dengan demikian,
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{\sin{\left(28 x \right)} d x}}}}{2} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{28} d u}}}}{2}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{28}$$$ dan $$$f{\left(u \right)} = \sin{\left(u \right)}$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{28} d u}}}}{2} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{28}\right)}}}{2}$$
Integral dari sinus adalah $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{56} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} - \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{56}$$
Ingat bahwa $$$u=28 x$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} + \frac{\cos{\left({\color{red}{u}} \right)}}{56} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}{4} + \frac{\cos{\left({\color{red}{\left(28 x\right)}} \right)}}{56}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=12$$$ dan $$$f{\left(x \right)} = \sin{\left(7 x \right)} \cos{\left(7 x \right)}$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + \frac{{\color{red}{\int{12 \sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}}}{4} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + \frac{{\color{red}{\left(12 \int{\sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}\right)}}}{4}$$
Misalkan $$$u=\sin{\left(7 x \right)}$$$.
Kemudian $$$du=\left(\sin{\left(7 x \right)}\right)^{\prime }dx = 7 \cos{\left(7 x \right)} dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$\cos{\left(7 x \right)} dx = \frac{du}{7}$$$.
Oleh karena itu,
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + 3 {\color{red}{\int{\sin{\left(7 x \right)} \cos{\left(7 x \right)} d x}}} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + 3 {\color{red}{\int{\frac{u}{7} d u}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{7}$$$ dan $$$f{\left(u \right)} = u$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + 3 {\color{red}{\int{\frac{u}{7} d u}}} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + 3 {\color{red}{\left(\frac{\int{u d u}}{7}\right)}}$$
Terapkan aturan pangkat $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ dengan $$$n=1$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + \frac{3 {\color{red}{\int{u d u}}}}{7}=\frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + \frac{3 {\color{red}{\frac{u^{1 + 1}}{1 + 1}}}}{7}=\frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + \frac{3 {\color{red}{\left(\frac{u^{2}}{2}\right)}}}{7}$$
Ingat bahwa $$$u=\sin{\left(7 x \right)}$$$:
$$\frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + \frac{3 {\color{red}{u}}^{2}}{14} = \frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56} + \frac{3 {\color{red}{\sin{\left(7 x \right)}}}^{2}}{14}$$
Oleh karena itu,
$$\int{4 \sin^{3}{\left(7 x \right)} \cos{\left(7 x \right)} d x} = \frac{3 \sin^{2}{\left(7 x \right)}}{14} + \frac{\cos{\left(14 x \right)}}{28} + \frac{\cos{\left(28 x \right)}}{56}$$
Sederhanakan:
$$\int{4 \sin^{3}{\left(7 x \right)} \cos{\left(7 x \right)} d x} = \frac{\sin^{4}{\left(7 x \right)}}{7} + \frac{3}{56}$$
Tambahkan konstanta integrasi (dan hapus konstanta dari ekspresi):
$$\int{4 \sin^{3}{\left(7 x \right)} \cos{\left(7 x \right)} d x} = \frac{\sin^{4}{\left(7 x \right)}}{7}+C$$
Jawaban
$$$\int 4 \sin^{3}{\left(7 x \right)} \cos{\left(7 x \right)}\, dx = \frac{\sin^{4}{\left(7 x \right)}}{7} + C$$$A