Integral dari $$$\frac{2 i n t}{x^{2} + 1}$$$ terhadap $$$x$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \frac{2 i n t}{x^{2} + 1}\, dx$$$.
Solusi
Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=2 i n t$$$ dan $$$f{\left(x \right)} = \frac{1}{x^{2} + 1}$$$:
$${\color{red}{\int{\frac{2 i n t}{x^{2} + 1} d x}}} = {\color{red}{\left(2 i n t \int{\frac{1}{x^{2} + 1} d x}\right)}}$$
Integral dari $$$\frac{1}{x^{2} + 1}$$$ adalah $$$\int{\frac{1}{x^{2} + 1} d x} = \operatorname{atan}{\left(x \right)}$$$:
$$2 i n t {\color{red}{\int{\frac{1}{x^{2} + 1} d x}}} = 2 i n t {\color{red}{\operatorname{atan}{\left(x \right)}}}$$
Oleh karena itu,
$$\int{\frac{2 i n t}{x^{2} + 1} d x} = 2 i n t \operatorname{atan}{\left(x \right)}$$
Tambahkan konstanta integrasi:
$$\int{\frac{2 i n t}{x^{2} + 1} d x} = 2 i n t \operatorname{atan}{\left(x \right)}+C$$
Jawaban
$$$\int \frac{2 i n t}{x^{2} + 1}\, dx = 2 i n t \operatorname{atan}{\left(x \right)} + C$$$A