Integral dari $$$- \frac{\cos{\left(93 x \right)}}{3}$$$

Temukan $$$\int \left(- \frac{\cos{\left(93 x \right)}}{3}\right)\, dx$$$.

Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=- \frac{1}{3}$$$ dan $$$f{\left(x \right)} = \cos{\left(93 x \right)}$$$:

$${\color{red}{\int{\left(- \frac{\cos{\left(93 x \right)}}{3}\right)d x}}} = {\color{red}{\left(- \frac{\int{\cos{\left(93 x \right)} d x}}{3}\right)}}$$

Misalkan $$$u=93 x$$$.

Kemudian $$$du=\left(93 x\right)^{\prime }dx = 93 dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dx = \frac{du}{93}$$$.

Oleh karena itu,

$$- \frac{{\color{red}{\int{\cos{\left(93 x \right)} d x}}}}{3} = - \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{93} d u}}}}{3}$$

Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{93}$$$ dan $$$f{\left(u \right)} = \cos{\left(u \right)}$$$:

$$- \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{93} d u}}}}{3} = - \frac{{\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{93}\right)}}}{3}$$

Integral dari kosinus adalah $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:

$$- \frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{279} = - \frac{{\color{red}{\sin{\left(u \right)}}}}{279}$$

Ingat bahwa $$$u=93 x$$$:

$$- \frac{\sin{\left({\color{red}{u}} \right)}}{279} = - \frac{\sin{\left({\color{red}{\left(93 x\right)}} \right)}}{279}$$

Oleh karena itu,

$$\int{\left(- \frac{\cos{\left(93 x \right)}}{3}\right)d x} = - \frac{\sin{\left(93 x \right)}}{279}$$

Tambahkan konstanta integrasi:

$$\int{\left(- \frac{\cos{\left(93 x \right)}}{3}\right)d x} = - \frac{\sin{\left(93 x \right)}}{279}+C$$

$$$\int \left(- \frac{\cos{\left(93 x \right)}}{3}\right)\, dx = - \frac{\sin{\left(93 x \right)}}{279} + C$$$A