Integral dari $$$\frac{\cos{\left(\frac{1}{x} \right)}}{x^{3}}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \frac{\cos{\left(\frac{1}{x} \right)}}{x^{3}}\, dx$$$.
Solusi
Misalkan $$$u=\frac{1}{x}$$$.
Kemudian $$$du=\left(\frac{1}{x}\right)^{\prime }dx = - \frac{1}{x^{2}} dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$\frac{dx}{x^{2}} = - du$$$.
Integralnya menjadi
$${\color{red}{\int{\frac{\cos{\left(\frac{1}{x} \right)}}{x^{3}} d x}}} = {\color{red}{\int{\left(- u \cos{\left(u \right)}\right)d u}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=-1$$$ dan $$$f{\left(u \right)} = u \cos{\left(u \right)}$$$:
$${\color{red}{\int{\left(- u \cos{\left(u \right)}\right)d u}}} = {\color{red}{\left(- \int{u \cos{\left(u \right)} d u}\right)}}$$
Untuk integral $$$\int{u \cos{\left(u \right)} d u}$$$, gunakan integrasi parsial $$$\int \operatorname{\kappa} \operatorname{dv} = \operatorname{\kappa}\operatorname{v} - \int \operatorname{v} \operatorname{d\kappa}$$$.
Misalkan $$$\operatorname{\kappa}=u$$$ dan $$$\operatorname{dv}=\cos{\left(u \right)} du$$$.
Maka $$$\operatorname{d\kappa}=\left(u\right)^{\prime }du=1 du$$$ (langkah-langkah dapat dilihat di ») dan $$$\operatorname{v}=\int{\cos{\left(u \right)} d u}=\sin{\left(u \right)}$$$ (langkah-langkah dapat dilihat di »).
Jadi,
$$- {\color{red}{\int{u \cos{\left(u \right)} d u}}}=- {\color{red}{\left(u \cdot \sin{\left(u \right)}-\int{\sin{\left(u \right)} \cdot 1 d u}\right)}}=- {\color{red}{\left(u \sin{\left(u \right)} - \int{\sin{\left(u \right)} d u}\right)}}$$
Integral dari sinus adalah $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:
$$- u \sin{\left(u \right)} + {\color{red}{\int{\sin{\left(u \right)} d u}}} = - u \sin{\left(u \right)} + {\color{red}{\left(- \cos{\left(u \right)}\right)}}$$
Ingat bahwa $$$u=\frac{1}{x}$$$:
$$- \cos{\left({\color{red}{u}} \right)} - {\color{red}{u}} \sin{\left({\color{red}{u}} \right)} = - \cos{\left({\color{red}{\frac{1}{x}}} \right)} - {\color{red}{\frac{1}{x}}} \sin{\left({\color{red}{\frac{1}{x}}} \right)}$$
Oleh karena itu,
$$\int{\frac{\cos{\left(\frac{1}{x} \right)}}{x^{3}} d x} = - \cos{\left(\frac{1}{x} \right)} - \frac{\sin{\left(\frac{1}{x} \right)}}{x}$$
Tambahkan konstanta integrasi:
$$\int{\frac{\cos{\left(\frac{1}{x} \right)}}{x^{3}} d x} = - \cos{\left(\frac{1}{x} \right)} - \frac{\sin{\left(\frac{1}{x} \right)}}{x}+C$$
Jawaban
$$$\int \frac{\cos{\left(\frac{1}{x} \right)}}{x^{3}}\, dx = \left(- \cos{\left(\frac{1}{x} \right)} - \frac{\sin{\left(\frac{1}{x} \right)}}{x}\right) + C$$$A