Integral dari $$$\sqrt{x^{2} + y^{2}}$$$ terhadap $$$x$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \sqrt{x^{2} + y^{2}}\, dx$$$.
Solusi
Misalkan $$$x=\sinh{\left(u \right)} \left|{y}\right|$$$.
Maka $$$dx=\left(\sinh{\left(u \right)} \left|{y}\right|\right)^{\prime }du = \cosh{\left(u \right)} \left|{y}\right| du$$$ (langkah-langkah dapat dilihat »).
Selain itu, berlaku $$$u=\operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}$$$.
Jadi,
$$$\sqrt{x^{2} + y^{2}} = \sqrt{y^{2} \sinh^{2}{\left( u \right)} + y^{2}}$$$
Gunakan identitas $$$\sinh^{2}{\left( u \right)} + 1 = \cosh^{2}{\left( u \right)}$$$:
$$$\sqrt{y^{2} \sinh^{2}{\left( u \right)} + y^{2}}=\sqrt{\sinh^{2}{\left( u \right)} + 1} \left|{y}\right|=\sqrt{\cosh^{2}{\left( u \right)}} \left|{y}\right|$$$
$$$\sqrt{\cosh^{2}{\left( u \right)}} \left|{y}\right| = \cosh{\left( u \right)} \left|{y}\right|$$$
Oleh karena itu,
$${\color{red}{\int{\sqrt{x^{2} + y^{2}} d x}}} = {\color{red}{\int{y^{2} \cosh^{2}{\left(u \right)} d u}}}$$
Terapkan rumus reduksi pangkat $$$\cosh^{2}{\left(\alpha \right)} = \frac{\cosh{\left(2 \alpha \right)}}{2} + \frac{1}{2}$$$ dengan $$$\alpha= u $$$:
$${\color{red}{\int{y^{2} \cosh^{2}{\left(u \right)} d u}}} = {\color{red}{\int{\frac{y^{2} \left(\cosh{\left(2 u \right)} + 1\right)}{2} d u}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{2}$$$ dan $$$f{\left(u \right)} = y^{2} \left(\cosh{\left(2 u \right)} + 1\right)$$$:
$${\color{red}{\int{\frac{y^{2} \left(\cosh{\left(2 u \right)} + 1\right)}{2} d u}}} = {\color{red}{\left(\frac{\int{y^{2} \left(\cosh{\left(2 u \right)} + 1\right) d u}}{2}\right)}}$$
Expand the expression:
$$\frac{{\color{red}{\int{y^{2} \left(\cosh{\left(2 u \right)} + 1\right) d u}}}}{2} = \frac{{\color{red}{\int{\left(y^{2} \cosh{\left(2 u \right)} + y^{2}\right)d u}}}}{2}$$
Integralkan suku demi suku:
$$\frac{{\color{red}{\int{\left(y^{2} \cosh{\left(2 u \right)} + y^{2}\right)d u}}}}{2} = \frac{{\color{red}{\left(\int{y^{2} d u} + \int{y^{2} \cosh{\left(2 u \right)} d u}\right)}}}{2}$$
Terapkan aturan konstanta $$$\int c\, du = c u$$$ dengan $$$c=y^{2}$$$:
$$\frac{\int{y^{2} \cosh{\left(2 u \right)} d u}}{2} + \frac{{\color{red}{\int{y^{2} d u}}}}{2} = \frac{\int{y^{2} \cosh{\left(2 u \right)} d u}}{2} + \frac{{\color{red}{u y^{2}}}}{2}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=y^{2}$$$ dan $$$f{\left(u \right)} = \cosh{\left(2 u \right)}$$$:
$$\frac{u y^{2}}{2} + \frac{{\color{red}{\int{y^{2} \cosh{\left(2 u \right)} d u}}}}{2} = \frac{u y^{2}}{2} + \frac{{\color{red}{y^{2} \int{\cosh{\left(2 u \right)} d u}}}}{2}$$
Misalkan $$$v=2 u$$$.
Kemudian $$$dv=\left(2 u\right)^{\prime }du = 2 du$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$du = \frac{dv}{2}$$$.
Dengan demikian,
$$\frac{u y^{2}}{2} + \frac{y^{2} {\color{red}{\int{\cosh{\left(2 u \right)} d u}}}}{2} = \frac{u y^{2}}{2} + \frac{y^{2} {\color{red}{\int{\frac{\cosh{\left(v \right)}}{2} d v}}}}{2}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(v \right)}\, dv = c \int f{\left(v \right)}\, dv$$$ dengan $$$c=\frac{1}{2}$$$ dan $$$f{\left(v \right)} = \cosh{\left(v \right)}$$$:
$$\frac{u y^{2}}{2} + \frac{y^{2} {\color{red}{\int{\frac{\cosh{\left(v \right)}}{2} d v}}}}{2} = \frac{u y^{2}}{2} + \frac{y^{2} {\color{red}{\left(\frac{\int{\cosh{\left(v \right)} d v}}{2}\right)}}}{2}$$
Integral dari kosinus hiperbolik adalah $$$\int{\cosh{\left(v \right)} d v} = \sinh{\left(v \right)}$$$:
$$\frac{u y^{2}}{2} + \frac{y^{2} {\color{red}{\int{\cosh{\left(v \right)} d v}}}}{4} = \frac{u y^{2}}{2} + \frac{y^{2} {\color{red}{\sinh{\left(v \right)}}}}{4}$$
Ingat bahwa $$$v=2 u$$$:
$$\frac{u y^{2}}{2} + \frac{y^{2} \sinh{\left({\color{red}{v}} \right)}}{4} = \frac{u y^{2}}{2} + \frac{y^{2} \sinh{\left({\color{red}{\left(2 u\right)}} \right)}}{4}$$
Ingat bahwa $$$u=\operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}$$$:
$$\frac{y^{2} \sinh{\left(2 {\color{red}{u}} \right)}}{4} + \frac{y^{2} {\color{red}{u}}}{2} = \frac{y^{2} \sinh{\left(2 {\color{red}{\operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}}} \right)}}{4} + \frac{y^{2} {\color{red}{\operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}}}}{2}$$
Oleh karena itu,
$$\int{\sqrt{x^{2} + y^{2}} d x} = \frac{y^{2} \sinh{\left(2 \operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)} \right)}}{4} + \frac{y^{2} \operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}}{2}$$
Dengan menggunakan rumus $$$\sin{\left(2 \operatorname{asin}{\left(\alpha \right)} \right)} = 2 \alpha \sqrt{1 - \alpha^{2}}$$$, $$$\sin{\left(2 \operatorname{acos}{\left(\alpha \right)} \right)} = 2 \alpha \sqrt{1 - \alpha^{2}}$$$, $$$\cos{\left(2 \operatorname{asin}{\left(\alpha \right)} \right)} = 1 - 2 \alpha^{2}$$$, $$$\cos{\left(2 \operatorname{acos}{\left(\alpha \right)} \right)} = 2 \alpha^{2} - 1$$$, $$$\sinh{\left(2 \operatorname{asinh}{\left(\alpha \right)} \right)} = 2 \alpha \sqrt{\alpha^{2} + 1}$$$, $$$\sinh{\left(2 \operatorname{acosh}{\left(\alpha \right)} \right)} = 2 \alpha \sqrt{\alpha - 1} \sqrt{\alpha + 1}$$$, $$$\cosh{\left(2 \operatorname{asinh}{\left(\alpha \right)} \right)} = 2 \alpha^{2} + 1$$$, $$$\cosh{\left(2 \operatorname{acosh}{\left(\alpha \right)} \right)} = 2 \alpha^{2} - 1$$$, sederhanakan ekspresi:
$$\int{\sqrt{x^{2} + y^{2}} d x} = \frac{x y^{2} \sqrt{\frac{x^{2}}{\left|{y}\right|^{2}} + 1}}{2 \left|{y}\right|} + \frac{y^{2} \operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}}{2}$$
Sederhanakan lebih lanjut:
$$\int{\sqrt{x^{2} + y^{2}} d x} = \frac{x \sqrt{x^{2} + y^{2}} + y^{2} \operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}}{2}$$
Tambahkan konstanta integrasi:
$$\int{\sqrt{x^{2} + y^{2}} d x} = \frac{x \sqrt{x^{2} + y^{2}} + y^{2} \operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}}{2}+C$$
Jawaban
$$$\int \sqrt{x^{2} + y^{2}}\, dx = \frac{x \sqrt{x^{2} + y^{2}} + y^{2} \operatorname{asinh}{\left(\frac{x}{\left|{y}\right|} \right)}}{2} + C$$$A