$$$\left[\begin{array}{cc}3 & 2\\2 & 3\\2 & -2\end{array}\right]\cdot \left[\begin{array}{cc}\frac{17}{225} & - \frac{8}{225}\\- \frac{8}{225} & \frac{17}{225}\end{array}\right]$$$

La calculadora multiplicará la matriz $$$3$$$ x $$$2$$$ $$$\left[\begin{array}{cc}3 & 2\\2 & 3\\2 & -2\end{array}\right]$$$ por la matriz $$$2$$$ x $$$2$$$ $$$\left[\begin{array}{cc}\frac{17}{225} & - \frac{8}{225}\\- \frac{8}{225} & \frac{17}{225}\end{array}\right]$$$, y se muestran los pasos.

Calculadora relacionada: Calculadora de matrices

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Si la calculadora no calculó algo o ha identificado un error, o tiene una sugerencia/comentario, escríbalo en los comentarios a continuación.

Tu aportación

Calcular $$$\left[\begin{array}{cc}3 & 2\\2 & 3\\2 & -2\end{array}\right]\cdot \left[\begin{array}{cc}\frac{17}{225} & - \frac{8}{225}\\- \frac{8}{225} & \frac{17}{225}\end{array}\right].$$$

Solución

$$$\left[\begin{array}{cc}{\color{DeepPink}3} & {\color{Fuchsia}2}\\{\color{DarkMagenta}2} & {\color{Green}3}\\{\color{BlueViolet}2} & {\color{DarkBlue}-2}\end{array}\right]\cdot \left[\begin{array}{cc}{\color{Magenta}\frac{17}{225}} & {\color{Crimson}- \frac{8}{225}}\\{\color{Peru}- \frac{8}{225}} & {\color{Blue}\frac{17}{225}}\end{array}\right] = \left[\begin{array}{cc}{\color{DeepPink}\left(3\right)}\cdot {\color{Magenta}\left(\frac{17}{225}\right)} + {\color{Fuchsia}\left(2\right)}\cdot {\color{Peru}\left(- \frac{8}{225}\right)} & {\color{DeepPink}\left(3\right)}\cdot {\color{Crimson}\left(- \frac{8}{225}\right)} + {\color{Fuchsia}\left(2\right)}\cdot {\color{Blue}\left(\frac{17}{225}\right)}\\{\color{DarkMagenta}\left(2\right)}\cdot {\color{Magenta}\left(\frac{17}{225}\right)} + {\color{Green}\left(3\right)}\cdot {\color{Peru}\left(- \frac{8}{225}\right)} & {\color{DarkMagenta}\left(2\right)}\cdot {\color{Crimson}\left(- \frac{8}{225}\right)} + {\color{Green}\left(3\right)}\cdot {\color{Blue}\left(\frac{17}{225}\right)}\\{\color{BlueViolet}\left(2\right)}\cdot {\color{Magenta}\left(\frac{17}{225}\right)} + {\color{DarkBlue}\left(-2\right)}\cdot {\color{Peru}\left(- \frac{8}{225}\right)} & {\color{BlueViolet}\left(2\right)}\cdot {\color{Crimson}\left(- \frac{8}{225}\right)} + {\color{DarkBlue}\left(-2\right)}\cdot {\color{Blue}\left(\frac{17}{225}\right)}\end{array}\right] = \left[\begin{array}{cc}\frac{7}{45} & \frac{2}{45}\\\frac{2}{45} & \frac{7}{45}\\\frac{2}{9} & - \frac{2}{9}\end{array}\right]$$$

Respuesta

$$$\left[\begin{array}{cc}3 & 2\\2 & 3\\2 & -2\end{array}\right]\cdot \left[\begin{array}{cc}\frac{17}{225} & - \frac{8}{225}\\- \frac{8}{225} & \frac{17}{225}\end{array}\right] = \left[\begin{array}{cc}\frac{7}{45} & \frac{2}{45}\\\frac{2}{45} & \frac{7}{45}\\\frac{2}{9} & - \frac{2}{9}\end{array}\right]\approx \left[\begin{array}{cc}0.155555555555556 & 0.044444444444444\\0.044444444444444 & 0.155555555555556\\0.222222222222222 & -0.222222222222222\end{array}\right]$$$A